Page 83 - Modeling of Chemical Kinetics and Reactor Design
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Reaction Mechanisms and Rate Expressions  53

                              Propagation

                                3. CH →       CH +   H *                              (1-224)
                                       *
                                           k 3
                                                    4
                                                 2
                                       5
                                     2
                                4. H +  C H  →      C H +  H 2                         (1-225)
                                                
                                                         *
                                     *
                                                k 4
                                            6
                                         2
                                                      2
                                                         5
                              Termination
                                                 
                                5. H +   C H  →     C H  6                             (1-226)
                                             *
                                     *
                                                 k 5
                                             5
                                                       2
                                          2
                                Applying the rate expressions to Equations 1-222, 1-223, 1-224, 1-225
                                                                                             *
                                                                                       *
                              and 1-226, and using the steady state approximation for CH , C H ,
                                                                                       3
                                                                                             5
                                                                                           2
                                    *
                              and H , for a constant volume batch reactor yields:
                                        )     dC CH 6
                                                  2
                                 − ( r     =−         = kC      + k C   C
                                                            2
                                   CH 6  net     dt      1  CH 6   2  CH 3 *  CH 6
                                    2
                                                                           2
                                                                                        (1-227)
                                                                          + kC H *  C CH 6  − k C H * C C H 5 *
                                                          4
                                                                        5
                                                                 2
                                                                               2
                                ( −r   )  =−  dC CH 3 *  = kC  C   − k C       = 0      (1-228)
                                                                     2
                                                               2
                                                                           2
                                   CH 3 *      dt      2  CH 3 *  CH 6  1  CH 6
                                       net
                                                  2
                                 − ( r  )  =−  dC CH 5 *  = kC   + k C    C
                                    2
                                   CH 5  net     dt       3  CH 5 *  5  CH 5 *  H *
                                                             2
                                                                        2
                                                                                        (1-229)
                                                                           − kC  * C  − k C  * C  = 0
                                                          2
                                                                         4
                                                                  2
                                                                                2
                                                             CH 3  CH 6    H   CH 6
                                ( −r H * ) net  =−  dC H *                              (1-230)
                                               dt
                                         = kC  H * C  CH 6  + k C H * C  C H 5 *  − k C C H 5 *  = 0
                                            4
                                                                        3
                                                          5
                                                    2
                                                                  2
                                                                            2
                              Rearranging Equations 1-228, 1-229, and 1-230 gives
                                 dC   *
                                        =  2  kC   −  k C   C      =  0                 (1-231)
                                   CH 3
                                               2
                                                               2
                                   dt       1  CH 6    2  CH 3 *  CH 6
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