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8.2.  ENERGY  TRANSPORT WITHOUT CONVECTION                          265


            or,

                                                     +-                     (8 2-40}
                                    Al(hA)    ALMk      A2(hB)
            in which the terms in the denominator indicate that the resistances are in series.
            The electrical circuit analogy for this case is given in Figure 8.16.





                    1
                    TA                   ------e                        TB

                      Figure 8.16  Electrical circuit analogy for Eq.  (8.2-40).


              In the literature, Eq.  (8.2-40) is usually expressed in the form

                                = AIUA(TA - TB) = &UB(TA  - TB)             (8.2-41)
           where the terms UA and UB are called the overall heat transfer coefficients.  Com-
           parison of  Eq.  (8.2-41) with Eq.  (8.2-40) gives UA and UB as





                                                                            (8.2-42)

           and





                                                                            (8.2-43)



           Example 8.7  Consider a cylindrical pipe  of  length L with inner and outer radii
            of R1  and  R2, .respectively, and investigate  how the rate of heat  loss changes  (1s  a
           function of  insulation thickness.
           Solution

            The immediate  reaction  of most  students  after  reading  the problem  statement  is
            “What’s the point  of  discussing  the  rate  of  heat  loss as a function  of  insulation
           thickness?  Adding  insulation  thickness obviously  decreases the rate  of heat  loss.”
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