Page 413 - Modelling in Transport Phenomena A Conceptual Approach
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9.5.  MASS TRANSFER WITH CONVECTION                                 393

            Constant wall mass flux
            As shown in Example 9.11, in the case of a constant wall mass flux, the concentra-
            tion gradient in the axial direction is constant and expressed in the form

                                                                            (9.543)

            Since we  are interested in the determination of  the Sherwood  number, it is ap
           propriate  to express &A/&   in  terms of  the Sherwood  number.  Note  that  the
            Sherwood number is given by


                                                                            (9.544)

           Therefore, Eq.  (9.543) reduces to

                                   bcA    Sh  (CAW - ‘Ab) DAB               (9.545)
                                   --  -
                                    8%         R2(VZ)
           Substitution of  Eq. (9.545) into Eq. (9.542) yields

                                                                            (9.5-46)

           In terms of  the dimensionless variables

                                                                            (9.547)

                                                7-
                                            [=-                             (9.548)
                                                R
           l3q.  (9.5-46) takes the form


                                                                            (9.549)

           It is important to note that 8 depends only on [ (or, r).
              The boundary conditions associated with Eq. (9.549) are


                                                                            (9.550)

                                      at  <=1      8=1                      (9.551)
           Note that EQs.(9.549)-(9.551) are identical with Eqs.  (9.3-46)-(9.3-48) with only
           exception that Nu is replaced by Sh . Therefore, the solution is
                                           Sh
                                    8 = 1 - - (3 -4t2+S4)                   (9.552)
                                           8
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