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                                                                          Chapter 9 Titrimetric Methods of Analysis  309
                 9B.7  Characterization Applications

                 Two useful characterization applications involving acid–base titrimetry are the de-
                 termination of equivalent weight, and the determination of acid–base dissociation
                 constants.

                 Equivalent Weights Acid–base titrations can be used to characterize the chemical
                 and physical properties of matter. One simple example is the determination of the
                 equivalent weight* of acids and bases. In this method, an accurately weighed sample
                 of a pure acid or base is titrated to a well-defined equivalence point using a mono-
                 protic strong acid or strong base. If we assume that the titration involves the trans-
                 fer of n protons, then the moles of titrant needed to reach the equivalence point is
                 given as
                                     Moles titrant = n ´moles analyte
                 and the formula weight is

                                          g analyte        g analyte
                                  FW =              =n  ´
                                        moles analyte    moles titrant
                 Since the actual number of protons transferred between the analyte and titrant is
                 uncertain, we define the analyte’s equivalent weight (EW) as the apparent formula
                 weight when n = 1. The true formula weight, therefore, is an integer multiple of the
                 calculated equivalent weight.
                                             FW = n ´EW

                 Thus, if we titrate a monoprotic weak acid with a strong base, the EW and FW are
                 identical. If the weak acid is diprotic, however, and we titrate to its second equiva-
                 lence point, the FW will be twice as large as the EW.

                            9
                     EXAMPLE  .6
                     A 0.2521-g sample of an unknown weak acid is titrated with a 0.1005 M
                     solution of NaOH, requiring 42.68 mL to reach the phenolphthalein end point.
                     Determine the compound’s equivalent weight. Which of the following
                     compounds is most likely to be the unknown weak acid?

                           ascorbic acid  C 6 H 8 O 6  FW = 176.1  monoprotic
                           malonic acid   C 3 H 4 O 4  FW = 104.1  diprotic
                           succinic acid  C 4 H 6 O 4  FW = 118.1  diprotic
                           citric acid    C 6 H 8 O 7  FW = 192.1  triprotic
                     SOLUTION
                     The moles of NaOH needed to reach the end point is
                                                                  –3
                             M b ´V b = 0.1005 M ´0.04268 L = 4.289 ´10 mol NaOH
                     giving an equivalent weight of
                                                      .
                                     g analyte       0 2521  g
                              EW =             =                = 58 78  g/mol
                                                                    .
                                                  .
                                   moles titrant  4 289  ´10 -3  mol
                 *See Section 2B.2 for a review of chemical equivalents and equivalent weights.
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