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48                        Gases and Collective Properties

             TABLE 3.1  Critical and van der Waals Constants

               Gas       T",      P",      v",         a,          b,
                          K      atm     ml mol- 1   l2 atm mor l   ml mor l
               He        5.3      2.26    57.8        0.0353      24.1
               H2       33.3     12.8     65.0        0.246       26.7
               N2      126.2     33.5     90.1        1.350       38.6
               CO      133       34.5     93.1        1.456       39.5
               O2      154.8     50.1     78          1.359       31.7
               CO2     304.2     72.9     94.0        3.61        42.8
              HCI      324.6     81.5     48          3.67        40.9
               NH3     405.5    111.3     72.5        4.20        37.4
               Cl2     417       76.1    124          6.49        56.2
               CH3 0H   513.2    78.5    118          9.53        67.1
               C2 HsOH   516     63.0    167         12.00        84.0

               CCl 4   556.4     45.0    276         19.54       126.8
               C6H6    562       48.6    260         18.46       118.6
              H2 O     647.4    218.3     56          5.45        30.4



             £Xample3.B

                Calculate the radius of the helium atom from its van der Waals constant b.
                The helium molecule contains a single atom. Consider each of these as a hard sphere
             of radius r. Then during a collision, the center of the second molecule gets to within dis-
             tance 2r from the center of the first. Volume (413)Jl"(2rY is thus excluded about the center
             of the first molecule.
                Dividing this excluded volume equally between the two molecules leads to

                                       .!in(2r)3 = 4inr3 = 16 nr3
                                        23          3      3
             excluded volume per molecule. The total for Avogadro's number of molecules is NA times
             as much, Setting this equal to b,


             solving for r,
                                             r=(16:J,



             and introducing the pertinent numbers yields

                                                       113
                                 'l{24.1 cm 3  mOl-I)
                        r =  [   \,                   ]  = 1.34 x 10-8 em = 1.34 A.
                            16( 3.1416 X 6.022 x 10 23   mOl-I)
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