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3.9 Gas-Liquid Isotherms                       49

             3.9 Gas-iliquid Isotherms

                Multiplying van der Waals equation by V2IP and rearranging leads to the form

                                     v 3  -[b+ RT)V 2 +~V _ ab =0.                   [3.52]
                                              P       P     P

             At a given temperature T and pressure P,  this is a cubic equation in volume V.  At high
             temperatures, only one root is real. But at a critical temperature and a critical pressure,
             the complex roots become real and equal. Going below this critical point on a pressure-
             volume plot, the three real roots gradually spread out. Equation (3.52) can be rewritten
             in the form
                                        (v - VI Xv -v 2Xv - V3 )=0,                  [3.53]
             in which VI>  V 2 ,  V3 are the three roots. At the critical point, where

                                                                                     [3.54]
                Equation (3.53) reduces to
                                                                                     [3.55]

             whence
                                                           3
                                        322
                                       V  -3VcV  +3Vc  V - Vc  = O.                  [3.56]
                Comparing (3.52) with T = Tc and P = Pc to (3.56) yields

                                             3V =b+ RTc                              [3.57]
                                               c
                                                      P.  '
                                                       c
                                                     a                               [3.58]
                                                     p'
                                                      c
                                                                                     [3.59]


             Solving for a,  b and R gives us
                                                                                     [3.60]

                                                b= Vc                                [3.61 ]
                                                    3'

                                               R= 8PcVc.                             [3.62]
                                                   3T c
                With these formulas, one can calculate a and b from the critical constants Pc and Vc
             for a given substance. Alternatively, one can substitute experimental values of P,  V,  and
             T for a particular region into (3.52) and solve for a and b. Because they vary, these para-
             meters should be determined for the temperature-pressure region to be represented.
                Experimental data for a particular substance are plotted in figure  3.2.  Each curve
             shows how the pressure varies with volume at a given temperature. Because the tem-
             perature is fixed along it, each curve is called an isotherm.
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