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Discretized PDEs with more than two spatial dimensions              293



                                             (b)
                  (a)                                 BC6 T(x, y, z = 0) = T b
                                          z = 0
                                        z = −d 1


                                        z = −D
                                                         BC5 ∂T/∂z = 0  heat generation material
                                    ceramic material
                                                    BC2 ∂T/∂y = 0
                                  (c)                     ctatina      y = L
                                               setr
                                                            dain
                                                        t 1
                                      BC3                   r 1          BC4
                                     ∂T/∂x = 0                         ∂T/∂x = 0
                                                          r 2


                                                              setr
                                                         t 2
                                                                        y = 0
                                          x = 0     BC1 ∂T/∂y = 0    x = L
                  Figure 6.18 Stove top geometry: (a) 2 × 2 grid of heating elements; (b) side view of an individual
                  element in a periodic array; (c) top view of an individual element.
                  regions,

                                       1,  if (χ, η, ζ) is within an annular region
                          H(χ, η, ζ) =                                              (6.170)
                                       0,  otherwise
                  This reduces the number of independent parameters to seven,
                                                                       SL 2
                        r 1 /L  t 1 /L  r 2 /L  t 2 /L  a ≡ L/D  b ≡ d 1 /L  σ ≡    (6.171)
                                                                       T b λ
                  As we expect the solution to possess the symmetry

                             θ(χ, η, ζ) = θ(−χ, η, ζ)  θ(χ, η, ζ) = θ(χ, −η, ζ)     (6.172)

                  we restrict the domain to 0 ≤ χ ≤ 1/2, 0 ≤ η ≤ 1/2 (dashed lines in Figure 6.18), and
                  enforce symmetry at χ = 0,η = 0, to yield the boundary conditions:
                                                  1    1          ∂θ
                           BC 1 η = 0     0 ≤ χ ≤    −   ≤ ζ ≤ 0     = 0
                                                  2    a          ∂η
                                     1            1    1          ∂θ
                           BC 2 η =       0 ≤ χ ≤    −   ≤ ζ ≤ 0     = 0
                                     2            2    a          ∂η
                                                  1    1          ∂θ
                           BC 3 χ = 0     0 ≤ η ≤    −   ≤ ζ ≤ 0     = 0
                                                  2    a          ∂χ                (6.173)
                                      1           1    1          ∂θ
                           BC 4 χ =       0 ≤ η ≤    −   ≤ ζ ≤ 0     = 0
                                      2           2    a          ∂χ
                                       1          1          1    ∂θ
                           BC 5 ζ =−      0 ≤ χ ≤    0 ≤ η ≤         = 0
                                       a          2          2    ∂ζ
                                                  1          1
                           BC 6 ζ = 0     0 ≤ χ ≤    0 ≤ η ≤      θ = 0
                                                  2          2
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