Page 350 - Numerical Methods for Chemical Engineering
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Brownian dynamics and SDEs                                          339



                  force and allow the drag force to dissipate the kinetic energy. The particle motion then
                  follows

                                     dV x                            ζt
                                   m     =−ζ V x ⇒ V x (t) = V x (0) exp −          (7.120)
                                      dt                              m
                  Therefore, the velocity correlation time is
                                          m     4    3     1       2ρR 2
                                       =    =    πρR            =                   (7.121)
                                    τ V x
                                          ζ     3        6πµR       9µ
                                                                            3
                                                                                    −3
                                                                       3
                  Fortheexamplecaseofaneutrallybuoyantparticleinwater, ρ = 10 kg/m ,µ = 10 Pa s.
                  For a very small particle with a diameter of 10 nm, on the size of macromolecules, the
                  velocity autocorrelation time is
                                          3
                                     3
                                  (10 kg/m )(10 −8  m) 2  3−16+3   −10
                                ∼                   = 10      s = 10  s             (7.122)
                             τ V x       −3
                                       (10  Pa s)
                  Even for a much larger particle of 100 µm = 10 −4  m, the correlation time is still quite
                  short,
                                           3
                                      3
                                   (10 kg/m )(10 −4  m) 2  3−8+3   −2
                                 ∼                   = 10     s = 10  s             (7.123)
                              τ V x
                                       (10 −3  Pa s)
                                                                             , the results will
                  Now, if we take velocity measurements at times much further apart than τ V x
                  be independent and uncorrelated from each other. From the above analysis, we see that the
                  correlation times of a particle in water are quite short. Thus, in many applications where
                                                                                      ,we
                  we are only concerned with the dynamics of the particle on time scales larger than τ V x
                  can neglect the effect of velocity correlation and derive our governing equation in the limit
                     → 0. Even in this limit, however, we must have a nonzero value of  V x (0)V x (0) =
                  τ V x
                        2
                   [V x (0)]  ; therefore, we write our approximate velocity autocorrelation as
                                              V x (t)V x (0) = 2Dδ(t)               (7.124)
                  where δ(t)isthe Dirac delta function:
                                     1         x 2     '  +∞
                         δ(t) = lim  √   exp −               f (t)δ(t)dt = f (0)    (7.125)
                               σ→0 σ 2π        2σ  2
                                                        −∞
                  Strictly speaking, the Dirac delta function is not a function at all, but is rather defined solely
                  through the integral relation in (7.125). See the discussion of the theory of distributions in
                  Stakgold (1979).
                    To see that D is consistent with the common definition of the diffusivity, we compute the
                  average displacement over the time period [0, t],
                                                      t
                                                    '
                                              x(t) =   V x (t 1 )dt 1               (7.126)
                                                      0
                  with
                                                             t
                              = '  t        '  t        >  ' '  t
                          2
                    [ x(t)]  =     V x (t 1 )dt 1  V x (t 2 )dt 2  =   V x (t 1 )V x (t 2 ) dt 1 dt 2  (7.127)
                                 0            0             0  0
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