Page 230 -
P. 230

5.1. Linear Stationary Iterative Methods  213


        Theorem 5.6 (of Kahan; Ostrowski and Reich)


          (1)   M SOR(ω) ≥|1 − ω| for ω  =0.
          (2) If A is symmetric and positive definite, then

                               M SOR(ω) < 1  for ω ∈ (0, 2) .

        Proof: See [16, pp. 91 f.].

          Therefore, we use only ω ∈ (0, 2). For a useful procedure we need more
        information about the optimal relaxation parameter ω opt,given by

                          M SOR(ω opt ) =min   M SOR(ω) ,
                                       0<ω<2
        and about the size of the contraction number. This is possible only if the
        ordering of equations and unknowns has certain properties:
        Definition 5.7 Amatrix A ∈ R    m,m  is consistently ordered if for the
        partition (5.18), D is nonsingular and
                            C(α):= α −1 D −1 L + αD −1 R
        has eigenvalues independent of α for α ∈ C\{0}.

        There is a connection to the possibility of a multi-colour ordering, because
        a matrix in the block form (5.39) is consistently ordered if it is block-
        tridiagonal (i.e., A ij =0 for |i − j| > 1) and the diagonal blocks A ii are
        nonsingular diagonal matrices (see [28, pp. 114 f.]).
          In the case of a consistently ordered matrix one can prove a relation
        between the eigenvalues of M J , M GS ,and M SOR(ω) .Fromthiswecan see
        how much faster the Gauss–Seidel method converges than Jacobi’s method:
        Theorem 5.8 If A is consistently ordered, then
                                      2
                                 (M J ) =  (M GS ) .

        Proof: For a special case see Remark 5.5.2 in [16].
          Due to (5.4) we can expect a halving of the number of iteration steps,
        but this does not change the asymptotic statement (5.27).
          Finally, in the case that Jacobi’s method converges the following theorem
        holds:
        Theorem 5.9 Let A be consistently ordered with nonsingular diagonal ma-
        trix D, the eigenvalues of M J being real and β :=  (M J ) < 1. Then we have
        for the SOR method:
                          2
          (1) ω opt =        2 1/2  ,
                    1+ (1 − β )
   225   226   227   228   229   230   231   232   233   234   235