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9.6 Ground state of the helium atom              259

                        Variation method treatment
                        As a normalized trial function ö for the determination of the ground-state
                        energy by the variation method, we select the unperturbed eigenfunction
                         (0)
                        ø (r 1 , r 2 ) of the perturbation treatment, except that we replace the atomic
                        number Z by a parameter Z9

                                                ö ˆ ö 1 ö 2
                                                              3=2
                                                     1    Z9
                                               ö 1 ˆ            e ÿ Z9r 1 =a 0            (9:88)
                                                    ð 1=2  a 0
                                                              3=2
                                                     1    Z9
                                               ö 2 ˆ            e ÿ Z9r 2 =a 0
                                                    ð 1=2  a 0
                        The parameter Z9 is an effective atomic number whose value is determined by
                        the minimization of E in equation (9.2). Since the hydrogen-like wave func-
                        tions ö 1 and ö 2 are normalized, we have
                                                 hö 1 jö 1 iˆhö 2 jö 2 iˆ 1               (9:89)
                          The quantity E is obtained by combining equations (9.2), (9.79), (9.88), and
                        (9.89) to give
                               *                        +   *                        +
                                         2         2                  2         2
                                        "                            "
                                            2   Ze9                      2   Ze9

                           E ˆ ö 1 ÿ       = ÿ         ö 1  ‡  ö 2 ÿ    = ÿ         ö 2

                                            1
                                                                         2

                                       2m e      r 1                2m e      r 2
                                  *               +

                                           2
                                          e9
                                ‡   ö 1 ö 2      ö 1 ö 2                                  (9:90)

                                          r 12
                        Note that while the trial function ö ˆ ö 1 ö 2 depends on the parameter Z9, the
                        Hamiltonian operator contains the true atomic number Z. Therefore, we rewrite
                        equation (9.90) in the form
                                *                        +    *                  +

                                        " 2          2                       2
                                             2   Z9e9               (Z9 ÿ Z)e9

                           E ˆ ö 1 ÿ       = ÿ          ö 1  ‡  ö 1             ö 1
                                             1
                                       2m e       r 1                   r 1
                                  *                         +   *                   +

                                           " 2         2                        2
                                                2   Z9e9               (Z9 ÿ Z)e9

                                ‡   ö 2 ÿ     = ÿ          ö 2  ‡  ö 2             ö 2
                                                2
                                          2m e       r 2                  r 2
                                  *                +

                                            2
                                           e9
                                ‡   ö 1 ö 2      ö 1 ö 2                                  (9:91)

                                          r 12
                        The ®rst term on the right-hand side is just the energy of a hydrogen-like atom
                                                              2
                                                           2
                        with nuclear charge Z9, namely, ÿZ9 e9 =2a 0 . The third term has the same
                        value as the ®rst. The second term is evaluated as follows
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