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Rays and Waves    245



          8.3 Small-Wavelength Limit in the Position
                Representation. II: The Transport
                Equation and the Field Estimate
               After we chose 	 to satisfy the eikonal equation, the remainder of
               Eq. (8.3) can be written as
                                                 1
                                            2       2
                               2∇ A·∇	 + A∇ 	 +   ∇ A = 0           (8.23)
                                                 ik
               Again, the key to the asymptotic treatment that follows is to regard k
               as a parameter that takes very large values.


               8.3.1 The Debye Series Expansion
               The amplitude Ais now written as a so-called Debye series of the form
                                            ∞
                                                 r
                                           ,   A j ( )
                                       r
                                     A( ) =                         (8.24)
                                               (ik) j
                                            j=0
               Then, upon substitution of Eq. (8.24), Eq. (8.23) can be written as
                                   ∞
                                   ,
                              2        1                  2    2
                2∇ A 0 ·∇	 + A 0 ∇ 	 +   j  2∇ A j ·∇	 + A j ∇ 	 +∇ A j−1 = 0
                                      (ik)
                                   j=1
                                                                    (8.25)
               Since k is used as an asymptotic parameter, the coefficient of each
               power of k is made to vanish independently. This gives a hierarchy of
               linked equations for each of the A j of the form
                                      2
                       2∇ A 0 ·∇	 + A 0 ∇ 	 = 0                    (8.26a)
                                              2
                                      2
                       2∇ A j ·∇	 + A j ∇ 	 =−∇ A j−1 ,  j = 1, 2, ...  (8.26b)

               8.3.2 The Transport Equation and Its Solution
               Equation (8.26a) can be solved to find A 0 , and in principle each A j
               can be found successively in terms of the previous one by solving
               Eq. (8.26b). For sufficientlylargek,however, A ≈ A 0 ,soonly Eq.(8.26a)
               will be considered. Notice that by multiplying both sides by A 0 , this
               equation can be rewritten as

                                           2
                                      ∇· A ∇	 = 0                   (8.27)
                                           0
               This expression is known as the transport equation. To solve it, consider
               integrating both sides over the volume occupied by a segment of an
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