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256   Chapter Eight


               8.6.2 Asymptotic Treatment and Ray
                      Equations
               Approaches 1 and 2 mentioned in Sec. 8.2 can be used to separate
               Eq. (8.55). For approach 2, it is assumed that both B and   are real,
               and Eq. (8.55) is separated into real and imaginary parts. This leads to
               a momentum-space flux-line formalism where no two trajectories ever
               have the same optical momentum at a given z, although they can cross
               freely in position. (For quantum mechanics, the equivalent procedure
               would lead to a momentum-space Bohmian formalism.) However,
               except for very simple refractive index distributions, the two resulting
               equations would be very complicated and would involve terms of
               many orders in k. This approach is therefore not considered further.
                 Ontheotherhand,approach1,whichcorrespondstotheasymptotic
               treatment, is tractable. We start by expanding B as a Debye series:

                                             ∞
                                             ,
                                                 B j
                                    B(p,z) =                        (8.56)
                                                (ik)  j
                                             j=0
               The substitution of this series into Eq. (8.55) gives analogs of the
               eikonal and transport equations
                                                    2
                                                ∂            ∂
                                           2            2
                                         |p| +       = n   −   ,z  (8.57a)
                                                ∂z           ∂p

                 ∂   2  ∂    1 ∂     2  ∂n 2  ∂
                    B 0    +     · B 0     −    ,z   = 0           (8.57b)
                ∂z     ∂z    2 ∂p      ∂x     ∂p
                                                                ¯
                 Equation (8.57a) can be solved by parameterizing p = P(z,  ) and
               defining
                                              ∂
                                    ¯            ¯
                                    X(z,  ) =−  (P,z)               (8.58)
                                              ∂p
                                            ∂
                                                ¯
                                    ¯ H(z,  ) =  (P,z)              (8.59)
                                             ∂z
               Notice that the derivative with respect to z of both sides of Eq. (8.58)
               gives

                                                     2
                                           ∂  ∂     ∂
                                 ˙ ¯    ˙ ¯
                                X =− P ·         −                  (8.60)
                                          ∂p  ∂p   ∂p ∂z
               To eliminate the cross-derivative term, let us consider the vector
               derivative with respect to the transverse momentum of both sides
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