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254   Chapter Eight



          8.6 Small-Wavelength Limit in the
                Momentum Representation
               In the asymptotic approach presented in Secs. 8.2 and 8.3, the field es-
               timate at a point is only due to the rays that go through that point. That
               is, rays are completely local entities. This approach leads to problems
               at caustics, where there is an infinite density of rays. An alternative
               asymptotic approach is presented in this section, where instead of
               working with the field as a function of r, we use its Fourier transform
               over the transverse coordinates, defined as

                                  k
                     ˜ U( p x ,p y ,z) =  U(x, y, z) exp(−ikx · p) dx dy  (8.50)
                                 2
               where x = (x, y) and p = ( p x ,p y ). While the derivation presented in
               the next few pages is in many ways analogous to that in Secs. 8.2 and
               8.3, it is appreciably more cumbersome. Those readers who prefer to
               do so can jump directly to the final result, given in Eq. (8.74).


               8.6.1 The Helmholtz Equation in the
                      Momentum Representation
               In free space, the transverse Fourier transform in Eq. (8.50) is known
                                              21
               as the angular spectrum representation. In a smoothly inhomogeneous
               medium, ˜ U satisfies an equation corresponding to the Fourier trans-
               formation of both sides of Eq. (8.1):

                                      ∂ 2       i ∂
                               2  2         2 2
                            − k |p| +    + k n      ,z   ˜ U = 0    (8.51)
                                      ∂z 2      k ∂p
               Here a function evaluated at a derivative is to be interpreted in terms
               of its Taylor expansion:

                                             j
                                    ∞
                    i ∂            ,   1  i
                           ˜
                 2
                n      ,z U(p,z) =
                   k ∂p                j!  k
                                    j=0
                                                      j
                                             ←− −→
                                              ∂
                                                  ∂
                                       2
                                   × n (x,z)    ·      ˜ U(p,z)      (8.52)
                                              ∂x ∂p
                                                              x=(0,0)
               where the arrows indicate the direction in which the derivatives act.
                                              2
               Notice that it is assumed here that n is an analytic function and, for
               convenience, the Taylor expansion is carried out around x = (0, 0).
               It turns out, however, that the asymptotic results of this section are
               independent of the point of expansion, and they hold as long as n is
               continuous.
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