Page 305 - Physical Principles of Sedimentary Basin Analysis
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9.1 Equation for flexure of a plate            287



                         z



                                                                  z(x)
                                                 φ  R





                                                   α 2
                                           α 1                          x
                                                   dx
            Figure 9.4. The radius of curvature for a point along an arbitrary curve.

            or in terms of derivation as
                                            d         du
                                       1   du  (arctan u)  dx
                                         =                                     (9.19)
                                       R         ds
                                                 dx
                                                        2
                                                                   2
                                                              2
            where u = dz/dx. From the length of a line element ds = dx + dz it follows that
                                       ds   !
                                          =   1 + (dz/dx) 2                    (9.20)
                                       dx
            and we have
                                       d              1
                                        (arctan u) =     .                     (9.21)
                                      du           1 + u 2
            When (9.20) and (9.21) are inserted into expression (9.19) for the radius of curvature
            we get
                                               2
                                      1       d z/dx 2
                                                          .                    (9.22)
                                     R  = 
          2   3/2
                                           1 + (dz/dx)
            A slightly bent curve has dz/dx 
 1 and we can make the approximation

                                                  2
                                            1    d z
                                              ≈                                (9.23)
                                            R   dx 2
            which is the expression used above.
                                           ∞



            Exercise 9.1 Show that dτ/dx =−  q(x )dx , where τ is the external torque (9.11).
                                          x
            Hint: make  τ = τ(x +  x) − τ(x).
                                        ∞

            Exercise 9.2 Show that V =    q(x )dx can be interpreted as the average shear
                                       x
            force along a vertical cross-section at x  = 0. Notice that it then follows that
            dV/dx = q(x).
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