Page 308 - Physical Principles of Sedimentary Basin Analysis
P. 308

290                        Flexure of the lithosphere

                 The load is divided by 2 because the integral is over only half the plate. The integral (9.32)
                 shows that V 0 is the surface part of the load, which is the part that is above z = 0. The
                 rest of the load, which is below z = 0, is the part that is filling the deflection. The solution
                 for the deflection tells us how deep the deflection becomes when it is filled with rock of
                 density   c .Itisshown in Note 9.2 that the solution to equation (9.31), with these four
                 boundary conditions, is

                                                          x
                                          x
                                                                x
                                        w(ˆ) = w max e −ˆ x  (cos ˆ + sin ˆ)        (9.33)
                 in terms of the dimensionless coordinate ˆ = x/α, where α is the characteristic length
                                                  x
                                                       
 1/4
                                                    4D
                                              α =          ,                        (9.34)
                                                     g
                 and the maximum deflection at x = 0is

                                                       V 0
                                              w max =      .                        (9.35)
                                                     2   gα
                 Notice that the length scale α is independent of the load. The deflection (9.33) is plotted
                 in Figure 9.7. The half-width ˆ 0 of the depression is given by w(ˆx 0 ) = 0, which has the
                                         x
                 solution
                                                      3π
                                                 ˆ x 0 =  .                         (9.36)
                                                      4
                 Figure 9.7 shows that the point load also creates a forebulge at the distance x 1 given by
                 dw/d ˆ = 0. We have
                      x
                                        dw              x
                                           x
                                          (ˆ 1 ) =−w max e −ˆ 1  sin ˆ 1 = 0        (9.37)
                                                             x
                                        d ˆ x
                 which has the solution ˆ 1 = π, and the height of the forebulge then becomes
                                      x
                 w 1 = w max e −π .
                   The distance to the forebulge is found to be roughly x 1 ≈ 250 km for the Hawaiian island
                 chain, see Figure 9.6, a distance that can be used to estimate the elastic thickness of the
                 lithosphere below the islands. The characteristic length scale becomes α = x 1 /π = 80 km.
                 The parameters E = 100 GPa, ν = 0.25,    = 600 kg m −3  give that the elastic thickness
                 of the lithosphere is h = 30 km. Such an estimate is denoted the effective elastic thickness.
                 It is the thickness an homogeneous plate would have, a plate with the same linear elastic
                 properties everywhere. The effective thickness is not a property of a plate that can be
                 directly observed, and it is normally used as a means of comparing elastic properties of
                 different plates.
                   Observations of the maximum deflection w max can in combination with the characteristic
                 length scale α be used to estimate the size of the point load. It follows from (9.35) that the
                 point load is
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