Page 312 - Physical Principles of Sedimentary Basin Analysis
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294                        Flexure of the lithosphere

                                       5




                                       0
                                   w [km]



                                      −5
                                                              point load (3)
                                                              Fourier solution
                                                              point load (1)
                                      −10
                                        0     200   400   600   800  1000
                                                      x [km]
                 Figure 9.8. A load is represented as three discrete point loads, and the deflection is the superposition
                 of the deflections from each point load. The three-point-load solution (3) is compared with the deflec-
                 tion caused by having all the mass at the center (1). A Fourier series solution for the rectangular point
                 load is also shown.

                                 9.3 Flexure from a point load on a broken plate
                 The plate beneath the Hawaiian island chain may be weak due to the volcanism that created
                 the islands. The weakness of the plate along the chain can be modeled assuming a point
                 load that acts on the edge of a broken plate. The assumption of a broken plate changes
                 the point-load model of the previous section only with respect to the boundary condition
                 at the end of the plate (at x = 0). For the infinite plate we had the symmetry condition
                 dw/dx = 0at x = 0. This boundary condition is now replaced by a zero bending moment,
                                                                           2
                                                                                2
                 and it follows from equation (9.9) that a zero bending moment implies d w/dx = 0. The
                 solution for the deflection then becomes
                                              x
                                                             x
                                            w(ˆ) = w max e  −ˆ x  cos ˆ             (9.51)
                                                x
                 where the dimensionless coordinate is ˆ = x/α, and where the maximum deflection is

                                                       V 0
                                              w max =      .                        (9.52)
                                                        gα
                 The characteristic length scale α is the same as for the unbroken plate, but the maximum
                 deflection of the broken plate is two times the deflection of the infinite plate (9.35).
                                                                                x
                   The half-width of the deflection, which is given as the solution at w = 0, is ˆ 0 = π/2.
                 It is seen to be π/4 shorter than the half- width for the unbroken plate. The distance to the
                 forebulge, which is given by dw/dx = 0, is ˆ 1 = 3π/4. The distance to the forebulge is
                                                     x
                 also π/4 less than the distance to the forebulge for the unbroken plate.
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