Page 317 - Physical Principles of Sedimentary Basin Analysis
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9.5 The deflection of a plate under compression     299


                           F                           w           F

            Figure 9.11. The buckling of a horizontal plate by a horizontal compressive force F.


            q(x) minus the counteracting buoyancy pressure   gw. A differential equation for the
            deflection is found after differentiating twice, and we get
                                     4
                                             2
                                    d w     d w
                                  D     + F     +   gw = q(x)                  (9.71)
                                    dx 4    dx 2
            (see Exercise 9.1 for how to carry out the first of the two differentiations). Equation (9.71)
            gives the deflection from the combined action of a surface load q(x) and a horizontal
            force F, when the plate is supported by a buoyancy pressure   w. We have already seen
            in Section 9.4 that a periodic surface load produces a periodic deflection, and we will see
            that the deflection from horizontal compression depends on the wavelength. The impact of
            the horizontal force F is therefore studied in the case of the same periodic surface load as
            in Section 9.4,
                                      q(x) = q 0 cos(2πx/λ),                   (9.72)
            where λ is the wavelength of the load. A constant surface load q 0 could have been added
            to the periodic load, in order to make it oscillate between 0 and q 0 , but it is left out since
            it only adds a constant subsidence q 0 /(  g) to the deflection. A periodic surface load can
            also be expressed using the wave number k = 2π/λ, which simplifies the expressions. The
            deflection in the case of the surface load (9.72) is found by guessing that the solution has
            the same form as the surface load
                                        w(x) = w 0 cos(kx).                    (9.73)
            By inserting solution (9.73) into equation (9.71) we get


                                         4     2
                                   w 0 Dk − Fk +   g = q 0                     (9.74)
            or
                                                 q 0
                                  w 0 =  
                   .                 (9.75)
                                             2
                                                      2
                                       k 2  (Dk +   g/k ) − F
            We first notice that zero compression (F = 0) leads to the same deflection as in Section 9.4
            for a periodic load. The next thing we notice is that the deflection increases with an increas-
            ing compressive force, but the compressive force cannot increase beyond the limiting
            force
                                              2
                                                       2
                                       F c = Dk +   g/k ,                      (9.76)
            which would imply an infinite deflection. The upper bound for the compressive force F c
            depends on the wave number (or alternatively on the wavelength). The critical force F c is
            seen to increase with decreasing wave numbers (increasing wavelengths), which means that
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