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22    INTRODUCTION TO PHYSICAL CHEMISTRY

                        Lord Kelvin (1824–1907) was a great thermodynamicist whom we shall meet quite
                      often in these pages. He noticed how the relationship in Equation (1.5) resembles the
                      equation of a straight line, i.e. takes the form


                                                     y = mx + c
                                                                                            (1.6)
                                           observed  gradient controlled  constant
                                            variable        variable

                      except without an intercept, i.e. c = 0. Kelvin obtained good-quality data for the
                      volume of a variety of gases as a function of temperature, and plotted graphs of
                      volume V (as y) against temperature T (as x) for each; curiously, however, he was
                      unable to draw a graph with a zero intercept for any of them.
                                        Kelvin then replotted his data, this time extrapolating each graph
              Note: degrees in the    till the volume of the gas was zero, which he found to occur at a
                                                           ◦
              Kelvin scale do not     temperature of −273.15 C; see Figure 1.5. He then devised a new
              have thedegreesym-      temperature scale in which this, the coldest of temperatures, was
              bol. The units have a   the zero. He called it absolute zero, and each subsequent degree
              capital K, but the noun  was equal to 1 C. This new scale of temperature is now called
                                                    ◦
              ‘kelvin’ has a small
                                      the thermodynamic (or absolute) scale of temperature, and is also
              letter.
                                      sometimes called the Kelvin scale.
                                        The relationship between temperatures T on the centigrade and
                      the absolute temperature scales is given by
                                                    ◦
                                               T in C = T in K − 273.15                     (1.7)
                                                     ◦
                      Equation (1.7) demonstrates how 1 C = 1K.

                                    0.04


                                    0.03
                                   Volume/m 3  0.02




                                    0.01


                                      0
                                        0        100       200       300       400
                                                         Temperature T/K

                      Figure 1.5 A graph of the volume V of a gas (as y) against temperature T (as x) is linear.
                                                                                              ◦
                      Extrapolating the gas’s volume suggests its volume will be zero if the temperature is −273.15 C
                      (which we call 0 K, or absolute zero)
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