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                  The Gibbs–Duhem Equation                                                                   Section 10.3
                  Activity coefficients of nonvolatile solutes can be found from vapor-pressure data  Determination of Activities
                                                                                                      and Activity Coefficients
                  using the Gibbs–Duhem equation, which we now derive. Taking the total differential
                  of G     n m [Eq. (9.23)], we find as the change in G of the solution in any infini-
                           i  i  i
                  tesimal process (including processes that change the amounts of the components of
                  the solution)
                    dG   d  a  n m    a  d1n m 2    a  1n dm   m   dn 2    a  n   dm    a  m   dn i
                                 i
                                                                 i
                                                                          i
                               i
                                            i
                                                              i
                                                         i
                                          i
                                                                                     i
                                                      i
                                                                             i
                            i         i           i                    i          i
                  The use of dG   S dT   V dP     m dn [Eq. (4.73)] gives
                                                  i  i  i
                                S dT   V dP    a  m   dn    a  n   dm    a  m   dn i
                                                    i
                                                                  i
                                                       i
                                                               i
                                                                          i
                                                i           i          i
                                          a  n dm   S dT   V dP   0                 (10.17)
                                                 i
                                              i
                                           i
                  This is the Gibbs–Duhem equation. Its most common application is to a constant-
                  T-and-P process (dT   0   dP), where it becomes

                                    a  n   dm    a  n   dG   0   const. T, P        (10.18)
                                            i
                                        i
                                                       i
                                                    i
                                     i           i
                      Equation (10.18) can be generalized to any partial molar quantity as follows. If Y

                  is any extensive property of a solution, then  Y      n Y i  [Eq. (9.26)] and  dY
                                                                 i
                                                                   i



                    n dY       Y  dn . Equation (9.25) with  dT    0    dP reads  dY      Y  dn .
                    i i  i     i  i  i                                              i  i  i
                  Equating these two expressions for dY, we get


                                  a  n dY   0  or   a  x dY   0   const. T, P       (10.19)
                                                       i
                                                          i
                                        i
                                     i
                                   i                i
                  where the form involving the mole fractions x was found by dividing by the total num-

                                                        i
                  ber of moles. The Gibbs–Duhem equation (10.19) shows that the Y  i ’s are not all inde-

                  pendent. Knowing the values of r    1 of the  ’s as functions of composition for a
                                                          Y
                                                           i

                  solution of r components, we can integrate (10.19) to find  .
                                                                    Y
                                                                     r
                      For a two-component solution, Eq. (10.19) with  Y    V (the volume) reads






                  x dV A    x dV B     0 or dV A     (x /x ) dV B  at constant T and P. Thus, dV A  and dV B
                           B
                                                   A
                                                 B
                   A
                  must have opposite signs, as in Fig. 9.9. Similarly, dm and dm must have opposite
                                                                 A
                                                                        B
                  signs when the solution’s composition changes at constant T and P.
                  Activity Coefficients of Nonvolatile Solutes
                  For a solution of a solid in a liquid solvent, the vapor partial pressure of the solute over
                  the solution is usually immeasurably small and cannot be used to find the solute’s activ-
                  ity coefficient. Measurement of the vapor pressure as a function of solution composition
                  gives P , the solvent partial pressure, and hence allows calculation of the solvent activ-
                        A
                  ity coefficient g as a function of composition. We then use the integrated Gibbs–Duhem
                               A
                  equation to find the solute activity coefficient g .
                                                          B
                      After division by n   n the Gibbs–Duhem equation (10.18) gives
                                           B
                                      A
                                      x   dm   x   dm   0   const. T, P             (10.20)
                                       A
                                           A
                                                B
                                                    B
                  From (10.6) we have m   m°(T, P)   RT ln g   RT ln x and
                                      A
                                                           A
                                                                     A
                                           A
                                 dm   RT d ln g   1RT>x 2 dx    const. T, P
                                    A
                                               A
                                                             A
                                                         A
                  Similarly, dm   RT d ln g   (RT/x ) dx at constant T and P. Substitution for dm A
                                                  B
                              B
                                          B
                                                      B
                  and dm in (10.20) gives after division by RT:
                        B
                              x  d ln g   dx   x  d ln g   dx   0   const. T, P     (10.21)
                                     A
                                                            B
                               A
                                                      B
                                                B
                                           A
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