Page 40 - Pipeline Rules of Thumb Handbook
P. 40

General Information  27

                   How to read descriptions that show            of degrees, the direction north-west would read, north 45
                     directions in terms of degrees              degrees west.
                                                                   Notice the small tract of land in Figure 6. The following
             In Figure 6, the north-south line and the east-west line  metes and bounds description will locate this tract: “Begin at
           divide the circle into 4 equal parts with each part containing  the beginning point, thence N 20 degrees west—200 feet,
           90 degrees. Several different directions are shown in this  thence N 75 degrees east—1,320 feet, thence S 30 degrees
           diagram with the number of degrees each varies east or west  east—240 feet, thence S 45 degrees west—420 feet, thence
           from the north and south starting points (remember that all  west—900 feet back to the point of beginning, containing so
           descriptions read from the north or south). North-west is a  many acres, etc.”
           direction that is half-way between north and west. In terms






























                                            Figure 6. Land description in terms of degrees.



           Size an air receiver for engine starting


                                                                      .
                                                                                 .
             Assume that the engine starter requires 16 standard cubic  53 5  ¥ 520  ¥ 36 624
                                                                 V =
           feet per second, that 10 seconds is required for starting and  144  ¥ (215 115 )
                                                                              -
           that you want to store enough air in the receiver for three
           starts. Assume the initial pressure in the receiver is 215psia
                                                                 V = 70.76cu.ft.
           and the final pressure is 115psia.
           Where:                                                Assume receiver is 30≤ or 2.5 feet inside diameter. Find the
                                                                 height of the receiver.
           V = Receiver volume, cu. ft.
           R = 53.5 for air                                               2
           T = Temperature (assumed constant at 520°R)              P  ¥  ID
                                                                 V =        ¥ H
           M  = Weight of air required to start the engine based on    4
               density of air = 0.0763 pounds per cu. ft.
           P = Pressure, pounds/sq. ft.                          Where:
                                                                 V = Volume to be contained in receiver, cu.ft.
             Example:                                            ID = Inside diameter of the receiver, feet
                                                                 H = Height of receiver, feet
           M = 16cu.ft./sec. ¥ 10sec./start ¥ 3 starts ¥ 0.0763 pounds   H = 14.4 feet
               per cu.ft.
             = 36.624 pounds                                     Use two receivers, each 7.5 feet high.
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