Page 59 - Pipeline Rules of Thumb Handbook
P. 59

46    Pipeline Rules of Thumb Handbook

         height of bend  = 2.513ft  = “V”. Take 8° as trial   ,   tive solution. Builders will take advantage of sag bends where
         T  = 5ft,    Incr.  = 0.5°. Note Calc. V is close to given V.   possible, depending on site conditions, space available, pipe
         This is a possible solution. Note, however, this is an alterna-  size, etc.






         Calculate maximum bend on cold pipe

                                                                 2
           How much of a bend can cold straight pipe take without  d D y  2 ZS A
                                                                     =                                         (9)
         over stressing? In other words, in laying straight pipe cross-  dl 2  3 EI
         country, what is the smallest radius of curvature possible
         within the allowable stress?                          Radius of curvature is given by the equation:
           The following is an analytical solution to these questions.
                                                                              32
                                                                            2
                                                                   È   Ê D   ˘
                                                                        dy ˆ
                                                                   Í 1 - Ë  dl ¯  ˙
                                                                   Î         ˚
                                                                R =                                           (10)
                                                                         2
                                                                        d D y
                                                                        dl 2
           The deflection equation for a length of straight pipe used
         as a cantilever beam with a concentrated end load is:  Substituting in Equation 10:
              Pl 3                                                              32
          Dy =                                           (1)       È          2 ˘
              3 EI                                                     Ê 2 lZS A ˆ
                                                                   Í 1 +  EI ¯  ˙
                                                                   Î   Ë 3     ˚
         The maximum stress in the beam is:                     R =                                           (11)
                                                                        2 ZS A
             M                                                           3 EI
          s =                                            (2)
              Z                                                        1 82   3EI
                                                                limR  =     =                                 (12)
         The maximum bending moment is:                         1Æ 0  2ZS A  2ZS A
                                                                       3EI
             MPl=                                        (3)
                                                                                     Notation
         If the allowable stress is S A , rewriting Equation 2 gives:
                                                               Dy deflection, in.
              M                                                  l length, in.
          S A =                                          (4)    P load, lb
              Z
                                                                E modulus of elasticity, lb/sqin.
              Pl                                                 I cross-sectional moment of inertia, in. 4
          S A =                                          (5)    S Stress, lb/sqin.
              Z
                                                                S A allowable stress, lb/sq in. from Code for Pressure Piping
          Pl =  ZS A                                     (6)    M bending moment, inch-pounds
                                                                Z section modulus, in. 3
         Rewriting Equation 1:                                  R Radius of curvature, in.

              ()  2  ZS l  2                                     Example. What is the smallest radius of curvature that can
               Pl l
                       A
          Dy =     =                                     (7)   be used without overstressing straight 24-in. Schedule 20
               3 EI   3 EI
                                                               seamless steel pipe ASTM 53? The pipe is at 70°F, and is to
         Taking the first and second derivatives of Equation 7:  be used for oil outside of refinery limits.
           D
          dy    21ZS A                                              3EI
              =                                          (8)    R =
             d1  3EI                                               2ZS A
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