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               60 Power systems engineering ± fundamental concepts

                      Electronic wattmeter
                      These instruments multiply the instantaneous voltage and current together and take
                      the average. Both digital and analog models are available. They are designed to be
                      used with CTs and VTs, (current transformers and voltage transformers) and they
                      come in single-phase and three-phase versions. Single-phase instruments have band-
                      widths up to several hundred kHz, so they give effective readings with distorted
                      waveforms such as are caused by rectifiers and inverters, provided the harmonic
                      content is not too great. See Figure 2.32.

                      Processing of sampled waveforms
                      The most exacting power measurements are in circuits with high-frequency switching
                      (as in power electronics with PWM [pulse-width modulation]), especially if the power
                      factor is low. In these cases the technique is to sample the voltage and current at high
                      frequency and then digitally compute the power from the voltage and current
                      samples: u [1, 2, . . . k .... N] and i [1, 2, . . . k .... N]. The average power over time T
                      is computed from:
                                    N
                                                 N
                                  1  X         1  X
                           P avg ˆ    p[k] t ˆ     u[k]i[k]  t,  where  T ˆ (N   1) t   (2:36)
                                 T            T
                                   kˆ1          kˆ1
                      Some digital processing oscilloscopes can perform this function, but there are spe-
                      cialist data acquisition systems with fast sampling and analog/digital conversion, and
                      they may include software for processing the equation (2.36).
                        The sampling process is illustrated in Figure 2.33. The double samples at the steep
                      edges in the voltage waveform show the ambiguity (uncertainty) that arises when the
                      sampling rate is too low relative to the frequency content of the sampled waveform.
                      This is a particular problem in power electronics, where the voltage may switch from
                      0±100% in the order of 1 ms. If we use a sampling frequency of 10 MHz to give 10
                      samples on each voltage switching, then if the fundamental frequency is 50 Hz we will
                                  7
                      need 1/50   10 ˆ 200 000 samples for just one cycle. This illustrates the tradeoff
                      between sample length and sampling frequency. The tradeoff is more difficult if a high
                      resolution is required (for example, 12-bit A/D conversion, a resolution of 1 part in 4096).
                      Wattmeter connections
                      Figure 2.34 shows the connection of three wattmeters to measure the total power in
                      three phases. The voltage coils of the wattmeters are returned to a common point
                      which effectively forms a false neutral point 0. This is convenient because the star
                      point of the load may not be available for connection (particularly if the load is an
                      induction motor). The instantaneous power is
                                                                                        (2:37)
                                                p ˆ u as i a ‡ u bs i b ‡ u cs i c
                      where i a is the instantaneous current in phase A and u as is the instantaneous voltage
                      across phase A, etc. In a three-wire connection, however,
                                                   i a ‡ i b ‡ i c ˆ 0                  (2:38)
                      and if we use this to eliminate i c from equation (2.37) we get

                                             p ˆ (u as   u cs )i a ‡ (u bs   u cs )i b
                                                                                        (2:39)
                                              ˆ u ac i a ‡ u bc i b
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