Page 330 - Power Electronics Handbook
P. 330

320   D.C. link frequency changers
                           45 m



                              -
                           40

                             -
                           35


                           30 -

                        J
                        0
                        .I-
                        o  25-
                        s?
                        In
                        m
                        0  .-
                        =  20-
                        E
                        z
                        c
                        E  15 -
                        (Ji
                        2   10  -









                            “0     20     40      60     80    100
                                    R.M.S.  fundamental as % of d.c.
                       Figure 13.38 Third harmonic content for the square modulated unidirectional wave of Figure
                        13.37
                       inverter  must  now  run  at twenty times  the output  frequency  required,
                       which can result in extra losses, and special techniques must be used to
                       minimise these losses and to increase high-frequency commutation times,
                       as described in Section 13.2.4.
                         In  the  voltage-control  technique  illustrated  in  Figure  13.37 a  square
                       wave is used  as the reference source.  A greater  reduction  in harmonic
                       content would be obtained if a sine wave was used as the reference, as in
                       Figure 13.40. The output pulses are now of  unequal width, but provided
                       the values of  XI, X2, X3, etc. are known the magnitude of  the harmonic
                       coefficient can  again be found from equation  (13.13). Equation  (13.14)
                       needs to be modified to take account of  the unequal pulse widths, and the
                       total r.m.s. content of the output is now given by equation (13.15).

                           VB  [IC                            I”  x  100         (13.15)
                                           {X(M + 1) - X(M)}
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