Page 233 - Pressure Vessel Design Manual

Special Designs 211

SO(60.219)
Pz = = + 1505
Example 2
P = 50 psi
P, = 7.5 psi P' = -7.5(60.219) = -225
2
Material: SA516-55, F, = 30 ksi
HI = VI tana = +350
S = 13.8 ksi
E = 0.85
H2 = Vz tan a! = - 533
Design temperature: 650°F

t, = 0.1875 in. H3 = V3tana = +86
t2 = 0.3125 in.
tCl = tCz = 0.3125 in. H4 = V4 tana = - 189

R, = 30.156 in.
RI, = 60.219 in. Hpl = PI tan@ = +358/ -54
d, = 60.31% in.
DI, = 120.438 in. Hp2 = P2 tana = - 717/ + 107
W 1 = 36,500 111

W2 = 41,100 lb H,1 = PR, = 50(30.156) = + 1508
PXR, = -7.5(30.156) = - 226
M = 2,652,000 in.-lb
M2 = 3,288,000 in.4
a = 25.46" H,z = PRL = SO(60.219) = + 3011
PXRL = -7.5(60.219) = - 452
-36,500 4(2,652,000)
v, = = +735
n60.3125 + n60.3 125'
V1
-- - +814
cos a
4(2,652,000)
-36,500
v0 = -- - = - 1121
- n60.3125 ~60.3125~
-- - - 1241
v2
cos 01
-41,100
\7;3 = -- + 4(3,288,000) = + 180
~120.438 ~~120.438~
V3
=
- + 199
cos a
-41,100 4(3,288,000)
v, = - = -396
v4
~120.438 ~120.438~ -- - -438
cos a
SO(30.156)
-
=
-113
p1 =-- = +754 P1 - +754 = +835, - 125
2 cosa! cos a cos o!
- 7.5(30.156) P2 +150S - 225
=
PI = = -113 -- - = +- 1666, - 249
-
2 cosa cos a cos CY