Page 190 - Principles of Applied Reservoir Simulation 2E
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Part II: Reservoir Simulation  175


             The cost of a simulation study can be estimated based on previous experi-
        ence with similar studies. As an example of how to estimate the cost for a black
        oil  simulation  study,  begin  by  calculating  the  product  of  the  number  of
        gridblocks  and  the  number  of  timesteps  denoted  by  GBTS.  Once  GBTS is
        known, it should  be related to the computer processing  (cpu)  time needed  to
        make a ran. The amount of cpu time per GBTS is determined by dividing the
        cpu time needed to make previous model runs by the number of GBTS in those
       runs. The product of GBTS and cpu time per GBTS gives total cpu time needed
        for a run. The cost of the study then depends on the number of runs that need
        to be made. The number of runs can be estimated by assuming that approxi-
        mately  100 runs will be needed to obtain a history match. A similar approach
        is  applied  to  estimating  the  cost  of  making  predictions.  Personnel  cost  Is
        approximately equal to computer cost for the study, This does not include the
        cost of data collection  and evaluation.



                                     Exercises

        Exercise  17.1  Data set EXAM10.DAT uses multiple Rock and PVT regions.
        Review EXAM 10.DAT and simplify the data set without altering model results.
        List the changes you make to the data set. Chapter 24.4 presents a description
       of Rock and PVT region data records.


        Exercise  17.2  A model has  10 * 10 x 4 gridblocks  and takes 5 minutes to ran
        100 timesteps.  Calculate cpu time per GBTS. Estimate how long it would take
       to make  100 runs with 200 timesteps  each.


       Exercise  17.3  (A) Use Eq. (17.3) to calculate the equivalent well block radius
       of a block with Ax = Ay = 200 ft. (B) Estimate shut in time for the Peaceman
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                                                              1
       correction using Eq. (17.1). Assume  <J> = 0.15, C T=  I  * 10~  psia" , jl = 2 cp and
       K=10md.
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