Page 283 - Probability and Statistical Inference
P. 283

260    5. Concepts of Stochastic Convergence

                                 Figure 5.3.4. We add that the earlier comments made in the context of the
                                 Figure 5.3.3 remain valid when the Figure 5.3.4 is inspected.
                                    In general, with a larger (than 10) sample size n, one will notice more
                                 clearly the symmetry in the resulting histograms around zero, whatever be the
                                 parent population pmf or pdf with finite σ(> 0).























                                     Figure 5.3.4. Histogram of 100 Random               Values
                                    from the Uniform(10 – a, 10 + a) Population when

                                    The three histograms presented in the Figures 5.3.2-5.3.4 are comparable
                                 to each other in the sense that the three parent populations under consider-
                                 ation have the same mean, µ = 10 and variance, σ  = 4. The reader should
                                                                             2
                                 pursue more explorations like these as exercises.
                                    Example 5.3.6 Let X , ..., X  be iid N(µ, σ ), –∞ < µ < ∞, 0 < σ < ∞. For
                                                                        2
                                                      1    n
                                 n ≥ 2, let                            be the sample variance. From
                                 (4.4.9), recall that                 where these Y ’s are the Helmert
                                                                                  i
                                 variables distributed as iid N(0, σ ). This implies that    is indeed a sample
                                                              2
                                 mean of (n – 1) iid random variables. The CLT then immediately leads us to
                                 conclude that                                       as n → ∞. But,
                                                                                      4
                                 one has                                            3σ  – σ  = 2σ .
                                                                                                4
                                                                                           4
                                 That is in this case, we have                   N (0, 2σ ) as n → ∞.
                                                                                       4
                                 Let us now denote V  = {n/(n – 1)}  and view it as a sequence of degenerate
                                                              1/2
                                                  n
                                 random variables to claim:    as n → ∞. Next, we apply Slutsky’s Theo-
                                 rem to conclude that                              as n → ∞. !
   278   279   280   281   282   283   284   285   286   287   288