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     10. Bayesian Methods  497
                           this with the fact that p(x) is increasing in x(∈ ℜ) to validate (10.7.7). In other
                           words, the expression of    is always positive. Also refer to the Exercises
                           10.7.2-10.7.3.  !
                              In the three previous examples, we had worked with the normal likelihood
                           function given   = θ. But, we were told that v was positive and hence we
                           were forced to put a prior only on (0, ∞). We experimented with the exponen-
                           tial prior for   which happened to be skewed to the right. In the case of a
                           normal likelihood, some situations may instead call for a non-conjugate but
                           symmetric prior for  . Look at the next example.
                              Example 10.7.4 Let X be N(θ, 1) given that   = θ where  (∈ ℜ) is the
                           unknown population mean. Consider the statistic T = X which is minimal
                           sufficient for θ given that   = θ. We have been told that (i)   is an arbitrary
                           real number, (ii)   is likely to be distributed symmetrically around zero, and
                           (iii) the prior probability around zero is little more than what it is likely with a
                           normal prior. With the N(0, 1) prior on  , we note that the prior probability of
                                                                    3
                           the interval (.01, .01) amounts to 7.9787 × 10  whereas with the Laplace
                           prior pdf h(θ) = ½e I(θ ∈ ℜ), the prior probability of the same interval
                                            |θ|
                           amounts to 9.9502 × 10 . So, let us start with the Laplace prior h(θ) for  .
                                               3
                           From the apriori description of   alone, it does not follow however that the
                           chosen prior distribution is the only viable candidate. But, let us begin some
                           preliminary investigation anyway.
                              One can verify that the marginal pdf m(x) of X can be written as
                           Next, one may verify that the posterior pdf of   given that X = x can be
                           expressed as follows: For all x ∈ ℜ and θ ∈ ℜ,
                           where b(x = {1  Φ(x + 1)}exp{(x + 1) /2}+F(x  1)exp{(x  1) /2}. The
                                                              2
                                                                                    2
                           details are left out as the Exercise 10.7.4. Also refer to the Exercises 10.7.5-
                           10.7.6.  !
                           10.8 Exercises and Complements
                              10.2.1 Suppose that X , ..., X  are iid with the common pdf f(x; θ) =
                                                  1
                                                        n
                           θe I(x > 0) given that v = θ where v(> 0) is the unknown parameter.
                             θx





