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260                  Radiochemistry  and  Nuclear  Chemistry


               very  slow  by  a  large  energy  of  activation  requirement  in  the  formation  of  a  necessary
               transition  state.
                For the exchange reaction  represented  above,  the rate of increase of AX* is equal  to  the
               rate of formation minus the rate of destruction of AX*.  The rate of formation is the product
               of the rate of reaction k r, the fraction of reactions which occur with an active BX*,  and the
               fraction  of reactions  which  occur with  an  inactive  AX.  Using  the  following  notation

                                            a  =  [AXI  +  [AX*]                   (9.17a)

                                            b  =  [BX]  +  [BX*]                   (9.17b)

                                               x  =  [AX*]                         (9.17e)


                                               y  =  [BX']                         (9.17d)
               the  rate of formation  kf is equal  to


                                           kf  =  k r (y/b)(a-x)/a                 (9.18a)

               In  a  similar  fashion,  the  rate of destruction  k d  is equal  to

                                           k d  =  k r (x/a)(b-y)/b                (9. lSb)

               Therefore

                                    dx/dt  =  kf  -  k d  =  k r (ay  -  bx)/(ab)   (9.19)

               The  solution  of this  equation  is

                                      In(1  -F)=   -k  r t  (a  +  b)/(ab)         (9.20)

               where F  =  x t Ix,,  (x**  is the value ofx t at t  =  co,  i.e.  equilibrium).  The rate of exchange
               k r  is  evaluated  from  the  slope  of  a  plot  log  (1  -  F)  versus  t.  If more  than  one  rate  of
               exchange  is  present  due  to  exchange  with  nonequivalent  atoms  in  a  reactant,  it  may  be
               difficult  to  resolve  this  curve  sufficiently  to  obtain  values  for  the  reaction  rates.  Isotopic
               exchange is a standard tool of the scientist studying the kinetics of chemical reactions whose
               half-lives  are longer  than a  minute.
                One  example  of  isotope  exchange  can  be  used  to  illustrate  the  value  of  these  studies.
               Consider the exchange between di- and trivalent chromium in HCIO 4 solutions.  If the total
               chromium  ion  concentration  is  0.1  M,  it  takes  14  days  for  the  exchange  to  reach  50%
               completion  at  room  temperature.  Inasmuch  as  the  di-  and  trivalent  cations  are  both
               positively  charged,  it  is  unlikely  that  they  can  approach  each  other  closely  enough  to
               exchange  an  electron  directly  to  allow  a  reversal  of  oxidation  state,  and  a  more  likely
               mechanism  is  that  an  anion  is  involved  as a  bridge between  the  two  cations  such  that  the
               intrusion  of the  anion  reduces  the repulsion  between  the  two  cations.  If this model  of the
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