Page 124 - Rock Mechanics For Underground Mining
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ROCK STRENGTH AND DEFORMABILITY










              Figure 4.23  Coulomb strength en-
              velopes in terms of (a) shear and nor-
              malstresses,and(b)principalstresses.

                                          Applying the stress transformation equations to the case shown in Figure 4.22
                                        gives

                                                               1
                                                                          1
                                                            n = (  1 +   3 ) + (  1 −   3 ) cos 2
                                                               2          2
                                        and
                                                               1
                                                             = (  1 −   3 ) sin 2
                                                               2
                                        Substitution for   n and s =   in equation 4.11 and rearranging gives the limiting
                                        stress condition on any plane defined by   as

                                                             2c +   3 [sin 2  + tan   (1 − cos 2 )]
                                                          1 =                                         (4.12)
                                                                sin 2  − tan   (1 + cos 2 )
                                          There will be a critical plane on which the available shear strength will be first
                                        reached as   1 is increased. The Mohr circle construction of Figure 4.23a gives the
                                        orientation of this critical plane as


                                                                       =   +                          (4.13)
                                                                         4   2
                                        This result may also be obtained by putting d(s −  )/d  = 0.
                                          For the critical plane, sin 2  = cos  , cos 2  =−sin  , and equation 4.12 reduces
                                        to

                                                                  2c cos   +   3 (1 + sin  )
                                                               1 =                                    (4.14)
                                                                        1 − sin
                                          This linear relation between   3 and the peak value of   1 is shown in Figure 4.23b.
                                        Note that the slope of this envelope is related to   by the equation
                                                                         1 + sin
                                                                  tan   =                             (4.15)
                                                                         1 − sin
                                        and that the uniaxial compressive strength is related to c and   by
                                                                        2c cos
                                                                     c =                              (4.16)
                                                                        1 − sin
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