Page 600 - Rock Mechanics For Underground Mining
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APPENDIX D  LIMITING EQUILIBRIUM ANALYSIS

                                        Mining depth for new failure. Substitution for W, A, T, V and U from equations
                                        D.1, 2, 3, 6 and 7 into equation D.9 and rearrangement gives a quadratic equation for
                                        H 2 , the new mining depth at which failure will occur

                                                      2

                                                   H 2  sin(  +   0 ) sin(  p2 +   0 ) sin(  p2 −   )
                                                                       2
                                                  c                  sin   0
                                                         2

                                                      H 2  sin(  +   0 ) cos      w Z w sin(  +   0 ) sin
                                               −2                          −
                                                     c          sin   0            2c sin   0

                                                       
 2
                                                     H 1  sin(  +   0 ) sin(  p1 +   0 ) sin(  p2 −   ) sin(  p2 −  )
                                               −                         2
                                                    c                  sin   0 sin(  p1 −  )
                                                        2

                                                     Z 1  cos   cos   p1 sin(  p2 −  ) sin(  p2 −  )
                                               +
                                                    c               sin(  p1 −  )
                                                        2

                                                     Z 2

                                               −         cos   cos   p2 sin(  p2 −   )
                                                    c
                                                          2

                                                   c    H c

                                               +            K sin(
 −   ) sin(  p2 −  )
                                                      c
                                                 2  Z 2 cos           w Z w

                                               +            cos   −      sin
                                                     c               2c
                                                           2

                                                   w    Z w

                                               +            cos(  p2 −   ) sin(  p2 −  ) = 0          (D.12)
                                                       c
                                        Equation D.12 gives a solution for the dimensionless group   H 2 /c in the form

                                                                  H 2       2    1/2
                                                                     = a + (a + b)                    (D.13)
                                                                 c
                                        where
                                                                               w Z w sin


                                                               sin   0 cos   −
                                                                                2c
                                                           a =                                        (D.14)
                                                                sin(  p2 +   0 ) sin(  p2 −   )

                                        and
                                                          
 2
                                                        H 1  sin(  p1 +   0 ) sin(  p2 −  )
                                                 b =
                                                       c     sin(  p1 −  ) sin(  p2 +   0 )
                                                             2
                                                            
                         2
                                                          Z 1  cos   cos   p1 sin(  p2 −  ) sin   0
                                                    −
                                                         c       sin(  +   0 ) sin(  p2 −   0 )
                                                            
 2               2
                                                          Z 2    cos   cos   p2 sin   0
                                                    +
                                                         c    sin(  +   0 ) sin(  p2 −   0 )
                                                               2
                                                              
                            2
                                                        c    H c   K sin(
 −   ) sin(  p2 −  ) sin   0
                                                    −
                                                           c     sin(  +   0 ) sin(  p2 +   0 ) sin(  p2 −   )

                                        582
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