Page 355 - Satellite Communications, Fourth Edition
P. 355

Error Control Coding  335

                                            Noisy signal     Clean signal
                                            .5V .7V –2V       1V 1V –1V



                                                                         Hard
                                    Optimum          Threshold                        Binary 1
                                                                       decision
                                   demodulator        detector                        output
                                                                       decoder



                                            Threshold
                                             level 0V
                                                            (a)


                                                     Noisy signal
                                                     .5V .7V –2V


                                                                 Soft
                                              Optimum                         Binary 0
                                                               decision
                                            demodulator        decoder        output


                                                            (b)
                              Figure 11.9 (a) Hard decision and (b) soft decision decoding.


                              output. In other words, a firm or hard decision is made on each bit at the
                              threshold detector.
                                With soft decision decoding (Fig. 11.9b), the received codeword is com-
                              pared in total with the known codewords in the set, 111 and 000 in this
                              example. The comparison is made on the basis of minimum distance
                              (the minimum distance referred to here is a Euclidean distance as
                              described shortly. This is not the same as the minimum distance intro-
                              duced in Sec. 11.2). To illustrate this, consider the first two points in an
                              x, y, z coordinate system. Let point P have coordinates x , y , z and
                                                                 1
                                                                                   1
                                                                                      1
                                                                                         1
                              point P have coordinates x , y , z . From the geometry of the situation,
                                                            2
                                                      2
                                                         2
                                    2
                              the distance d between the points is obtained from
                                             2          2           2          2
                                            d   (x   x )   (y   y )   (z   z )
                                                                              2
                                                              1
                                                                         1
                                                  1
                                                                   2
                                                       2
                                Treating the codewords as vectors and comparing the received code-
                              word on this basis with the stored version of 111 results in
                                                             2
                                                                           2
                                                 2
                                         (0.5   1)   (0.7   1)   (   2   1)   9.34
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