Page 381 - Schaum's Outline of Differential Equations
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364                       ANSWERS TO SUPPLEMENTARY PROBLEMS





         19.25.   Method:  ADAMS-BASHFORTH-MOULTON METHOD

                  Problem: / = -}>; y(0) = 1
                                 ft = 0.1
                  x n
                                                    True solution
                            py n         y n         Y(x)  = e~ x
                  0.0       —         1.0000000       1.0000000

                  0.1       —         0.9048375      0.9048374
                  0.2       —         0.8187309      0.8187308
                  0.3       —         0.7408184      0.7408182

                  0.4    0.6703231    0.6703199      0.6703201

                  0.5    0.6065332    0.6065303      0.6065307
                  0.6    0.5488136    0.5488110      0.5488116
                  0.7    0.4965869    0.4965845      0.4965853

                  0.8    0.4493302    0.4493281      0.4493290

                  0.9    0.4065706    0.4065687      0.4065697
                  1.0    0.3678801    0.3678784      0.3678794












         19.26.   Method:  ADAMS-BASHFORTH-MOULTON METHOD

                  Problem

                                 h = 0.2
                  x n
                                                    True solution
                            py n         y n      Y(x)  = x-y/9 + lnx 2
                  1.0       —         3.0000000      3.0000000

                  1.2       —         3.6722028      3.6722045
                  1.4       —         43541872       43541901

                  1.6       —         5.0444406      5.0444443
                  1.8    5.7419118    5.7418465      5.7418514

                  2.0    6.4455861    6.4455489      6.4455549
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