Page 244 - Schaum's Outline of Theory and Problems of Advanced Calculus
P. 244

CHAP. 10]  LINE INTEGRALS, SURFACE INTEGRALS, AND INTEGRAL THEOREMS             235


                                                  rF      @r  @r      @r  @r


                                                          @x  @y
                                                     ¼                                              ð15Þ
                                                 jrFj               @v 1  @v 2
                        [Now a conclusion of the theory of implicit functions is that from Fðx; y; zÞ¼ 0 (and under appro-
                     priate conditions) there can be produced an explicit representation z ¼ f ðx; yÞ of a portion of the surface.
                     This is an existence statement.  The theorem does not say that this representation can be explicitly
                     produced.]  With this fact in hand, we again let v 1 ¼ x; v 2 ¼ y; z ¼ f ðv 1 ; v 2 Þ. Then
                                                      rF ¼ F x i þ f y j þ F z k
                        Taking the dot product of both sides of (15) yields
                                                                  1
                                                       F z
                                                          ¼
                                                               @r

                                                      jrFj          @r


                                                               @v 1  @v 2

                        The ambiguity of sign can be eliminated by taking the absolute value of both sides of the equation.
                     Then
                                                                 2     2     2 1=2
                                             @r
                                                  @r    jrFj  ½ðF x Þ þðF y Þ þðF z Þ Š

                                                     ¼     ¼

                                             @v 1  @v 2  jF z j      jF z j
                     and the surface integral of   takes the form
                                                       2     2     2 1=2
                                                 ðð
                                                                       dx dy                        ð16Þ
                                                    ½ðF x Þ þðF y Þ þðF z Þ Š
                                                            jF z j
                                                  S
                        The formulas (14) and (16) also can be introduced in the following nonvectorial manner.
                        Let S be a two-sided surface having projection r on the xy plane as in the adjoining Fig. 10-4.
                     Assume that an equation for S is z ¼ f ðx; yÞ, where f is single-valued and continous for all x and y in r .
                     Divide r into n subregions of area  A p ; p ¼ 1; 2; .. . ; n, and erect a vertical column on each of these
                     subregions to intersect S in an area  S p .

















                                                           Fig. 10-4

                        Let  ðx; y; zÞ be single-valued and continuous at all points of S. Form the sum

                                                        n
                                                       X
                                                          ð  p ;  p ;  p Þ  S p                     ð17Þ
                                                       p¼1
   239   240   241   242   243   244   245   246   247   248   249