Page 406 - Schaum's Outline of Theory and Problems of Applied Physics
P. 406

CHAP. 31]                           SPHERICAL MIRRORS                                 391



                  In general, an object placed between the focal point and the center of curvature C of a concave mirror (that is,
              with p greater than f but less than 2 f ) will have a real, inverted image that is larger than the object.









                                                    Fig. 31-7


        SOLVED PROBLEM 31.5

              A pencil 12 cm long is placed at the center of curvature of a concave mirror whose focal length is 40 cm.
              Find the location, size, and nature of the image.

                  Since f = R/2 for a concave mirror, p = R = 2 f = 80 cm here. The image distance is therefore
                                              pf    (80 cm)(40 cm)
                                         q =      =             = 80 cm
                                             p − f  80 cm − 40 cm
              The image is real and at the same distance from the mirror as the object (Fig. 31-8). The height of the image is
                                              q             80 cm
                                       h =−h    =−(12 cm)        =−12 cm

                                              p           80 cm
              which is the same as the height of the object. The minus sign indicates an inverted image.
                  In general, an object placed at the center of curvature of a concave mirror has a real, inverted image the same
              size as the object and at the same distance from the mirror.









                               Fig. 31-8                                  Fig. 31-9


        SOLVED PROBLEM 31.6
              A cigar 15 cm long is placed 75 cm in front of a concave mirror whose focal length is 30 cm. Find the
              location, size, and nature of the image.
                  Here p = 75 cm and f = 30 cm, so the image distance is
                                              pf    (75 cm)(30 cm)
                                         q =      =             = 50 cm
                                             p − f  75 cm − 30 cm
              The image is real and on the same side of the mirror as the cigar (Fig. 31-9). The length of the image is
                                              q             50 cm

                                       h =−h    =−(15 cm)        =−10 cm
                                              p           75 cm
              which is smaller than the length of the cigar. The minus sign indicates an inverted image.

        SOLVED PROBLEM 31.7
              A reflecting telescope that uses a concave mirror whose radius of curvature is 4 m produces an image
              of the moon on a photographic plate. The moon’s diameter is approximately 3500 km, and it is about
   401   402   403   404   405   406   407   408   409   410   411