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320        FOURIER ANALYSIS OF DISCRETE-TIME SIGNALS AND SYSTEMS  [CHAP. 6



           6.19.  Find the  Fourier  transform of the sinusoidal sequence
                                           x[n] = cos Ron        lflolS

                     From  Euler's formula we have
                                              cos Ron = ;(ein~" + e-'   IJ n,
                 Thus, using Eq. (6.135) and the linearity property (6.42), we get
                                  X(R) = T[S(~ 0,) + 6(R + a,)]        IRI, Ia0I 5
                                                 -
                 which is illustrated in  Fig. 6-15. Thus,

                                 cos Ron - a[6(R - Ro) + 6(R+ a,)]       Ial, IRol r T       (6.137)


















                               Fig. 6-15  A cosine sequence and its Fourier transform.




           6.20.  Verify  the conjugation property (6.45), that  is,
                                                 x*[n] -X*(-R)
                     From  Eq. (6.27)
                                                 m
                                   .F(x*[n]) =  C  x*[n] e-inn =
                                               n = -m              n= -m




                 Hence,
                                                  x*[n] -X*( -0)


           6.21.  Verify the time-scaling property (6.491, that  is,


                     From Eq. (6.48)

                                           x[n/m] =x[k]          if  n = km, k  = integer
                                                                 ifnzkm
                 Then, by  Eq. (6.27)
                                                           m
                                            .F(-qrn)b1) C ~(,)bl e-jnn
                                                       =
                                                         ,,=  -m
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