Page 432 - Schaum's Outline of Theory and Problems of Signals and Systems
P. 432

CHAP.  71                       STATE SPACE ANALYSIS




                   Now from Eq. (7.65), for x(t ) = 0 and  to = 0,


                   However, by  the Cayley-Hamilton theorem  eA' can be expressed as





                   Substituting Eq. (7.136) into Eq. (7.135), we get





                   in view of  Eq. (7.134). Thus, qo is indistinguishable from the zero state and hence the system is
                   not observable. Therefore, if  the system is to be observable, then  Mo must  have rank  N.


             7.53.  Consider the system in Prob. 7.50.
                   (a)  Is the system controllable?
                   (6)  Is the system observable?
                   (a)  From the result from Prob. 7.50 we  have





                        Now

                        and by  Eq. (7.128) the controllability matrix is
                                                  M, = [b  Ab]  = [-1  -11



                        and  IM,I  = 0. Thus, it  has a rank  less than  2 and  hence the system is not controllable.
                   (b)  Similarly,





                        and by  Eq. (7.133) the observability matrix is




                        and  JMJ = - 2 # 0. Thus, its rank is 2 and hence the system is observable.
                           Note from the result from Prob. 7.50(b) that the system function H(s) has pole-zero
                        cancellation. As  in  the discrete-time case, if  H(s) has pole-zero cancellation, then  the
                        system cannot be both controllable and observable.


             7.54.  Consider the system shown in  Fig. 7-22.

                   (a)  Is the system controllable?
                   (b)  Is the system observable?
                   (c)  Find the system function  H(s).
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