Page 182 - Schaum's Outlines - Probability, Random Variables And Random Processes
P. 182
CHAP. 51 RANDOM PROCESSES
Fig. 5-6
Since X,'s are independent, we have
P(X1 = xl, X2 = x,, . . . , X, = x,) = P(Xl = x,)P(X, = x,) . . P(X, = x,) (5.67)
Thus, for the sample sequence of Fig. 5-3,
P(xl = 1, x2 = 0, x3 = 0, x4 = 1, x5 = 1, x6 = 1, x7 = 0, xs = 1, x9 = 1, Xl0 = 0) = p6q4
2 4 6 8
Fig. 5-7
