Page 248 - Schaum's Outlines - Probability, Random Variables And Random Processes
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CHAP.  61         ANALYSIS  AND  PROCESSING  OF  RANDOM  PROCESSES                 24 1



         6.43.  Let z(o) be the Fourier transform of  a random process X(t). If  %(o) is a white noise with zero
               mean  and  autocorrelation  function  q(o,)6(co1 - a,),  then  show  that  X(t) is  WSS  with  power
               spectral density q(o)/27r.
                   By Eq. (6.91),




               Then                                   ~[X(w)]ej'~~ 0
                                                               do
                                                                  =
               Assuming that X(t) is a complex random process, we have




                                                                   dw2
                                                                dw,
                                 --         ~[~(o,)~*(o,)]ej(~~~-"~~)
                                    1  "  "
                                 -- 4n2 [ 1 mq(col)b(w, - 02)e'(w1t-w2G do, do,
                                 -      oo
                                    1   rm

               which depends only on t - s = z. Hence, we conclude that X(t) is WSS. Setting t - s = z and o, = o in Eq.
               (6.1 78), we have







               in view of Eq. (6.24). Thus, we obtain Sx(o) = q(o)/2n.

         6.44.  Verify Eq. (6.104).
                   By Eq. (6.100),




                                                       m    co
               Then         R&,   Q2) = E[X(Q,)~*(Q,)] =   x ~[X(n)X*(rn)]e-j("~~-~~~)



               in view of Eq. (6.1 03).


         6.45.  Derive Eqs. (6.105) and (6.106).
                   If X(n) is WSS, then Rx(n, m) = R,(n  - m). By Eq. (6.103), and letting n - m  = k, we have
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