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From Global Balance to Local Non-Equilibrium



                Figure 6.9.  Two–dimensional tri-                   k
                                                       L
                angular element with nodal indi-         j
                                                              d  j    d
                ces i, j, k. The three vectors L  ,                    i       L i
                                       i
                L   and L   represent the edges
                 j      k
                connecting nodes j to k, k to i and i
                                                                   d
                to j, respectively. The cross sec-                  k
                tions for the fluxes are d  , d   and
                                   i  i
                d  .                            i                 L k                j
                 i
                             The discrete form of (6.90a) is found by assuming that ψ  varies linearly
                             along the edges connecting two nodes and thus is a linear function on the
                                                                               i j
                             two dimensional triangular element, e.g., defined by the nodes  ,   and k
                             in Figure 6.9. Therefore, the corresponding flux  D   is constant. Let us
                                                                       k
                             integrate on the part of the box associated with note   that lies in the ele-
                                          i j
                                                 k
                             ment defined by  ,   and  . This gives us two contributions from the sur-
                             face integral form the flux displacement vector

                                             ∫  Ds S =  D l d +  D l d  j         (6.91)
                                                 d
                                                       i i i
                                                              j j
                                             S k
                             where S   is the surface of the part of the box around node   lying in the
                                                                            k
                                   k
                             triangle  ij k,,(  )  . Here we introduced the unit vector in the respective
                                            ⁄
                                                         ⁄
                             directions l =  L L   and l =  L L  , that are associated with the box
                                      i    i  i     j    j  j
                             surface elements d   and d  . In terms of the electrostatic potential (6.91)
                                            i     j
                             reads
                                       k Tε ε d i        d j            d L +  d L j
                                                                               j
                              ∫  Ds S =  ------------------- ---- u –(  k  u ) +  ----- u –(  k  u ) =  ρ --------------------------  (6.92)
                                                                         i i
                                        B
                                           0 r
                                  d
                                                                       k
                                                      j
                                                                 i
                                                                            2
                                          q
                                              L
                                                         L
                              S k               i          j
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