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P. 229

Transport Theory
                             where we scaled the electrostatic potential in terms of the thermal voltage
                             according to
                                                        qψ
                                                    u =  ---------                (6.93)
                                                        k T
                                                         B
                             The r.h.s. of (6.92) is a product of the nodal value ρ   of the charge den-
                                                                       k
                                                                             k
                             sity and the area of the portion of the box surrounding node   that lies in
                             the element.  The discretization of (6.90b) and (6.90c) has to be per-
                             formed with care since we have already made assumptions on the poten-
                             tial. Introducing (6.89a) and (6.93) into (6.88a) yields the electron
                             current density

                                                       (
                                                          –
                                               j =  qD ∇nn∇u)                     (6.94)
                                                n     n
                             j   may be projected on an edge of the triangular element, say  L  , to
                              n                                                    k
                             give
                                                     ∂n  du  
                                           j   =  qD    – n   =  j l              (6.95)
                                            nk     n  l ∂   k  l d   n k
                                                            k
                             The projection  j nk   is assumed to be constant along the edge  L k  . This
                             constrains the element size to a length scale where the assumption is ful-
                             filled. On the other hand, the linear potential function on the edge

                                                 u –  u i
                                                  j
                                          ul() =  ---------------l +  u =  a l +  u  (6.96)
                                            k          k   i   k k   i
                                                   L k
                             leads to a differential equation for   along L k
                                                        n
                                                    dn        j nk
                                              J  nk  =  – α n =  ----------       (6.97)
                                                        k
                                                     l d     qD
                                                     k          n
                             Integrating  (6.97)  from  node  i   to   node   j   yields
                                     (
                                              (
                                                    ⁄
                                                                               n
                             J  =  [ Bu )n –  Bu )n ] L  . n   and n   are the values of   at nodes
                              nk       ji  j   ij  i  k  i     j
                                                        ⁄
                                                                  –
                                  j
                             i   and  , respectively. Bu(  ) =  x ( exp  u (  ) 1)   is the Bernoulli func-
                                                  ji           ji
                             tion for the argument u  =  u –  u  . Thus the flux of  j   related to node
                                                ji   j   i               n
                             k   enters (6.90b) to give
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