Page 210 - Shigley's Mechanical Engineering Design
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                                                                                              Deflection and Stiffness  185
                       Figure 4–20                    x
                                                        P
                       Notation for an eccentrically  A
                                                                  x
                       loaded column.

                                                               P
                                                 l

                                                             M
                                                              y
                                                                         x
                                               y            y
                                                    O   P            Pe
                                                      e
                                                                   P
                                                   (a)           (b)




                                               The solution of Eq. (a), for the boundary conditions that y   0 at x   0, l is

                                                                 [ (  l          ) (   )  (   )  ]                (b)
                                                                         P
                                                                                              P
                                                                                 P


                                                             y   e tan  2 EI    sin  EI  x    cos  EI  x   1
                                               By substituting x = l/2 in Eq. (b) and using a trigonometric identity, we obtain
                                                                            [ (   )  ]                         (4–47)
                                                                                            lP
                                                                             e sec
                                                                                  EI  2    1
                                               The magnitude of the maximum bending moment also occurs at midspan and is


                                                                                          l  P
                                                                  M max = P(e + δ) = Pe sec                    (4–48)
                                                                                         2   EI
                                               The magnitude of the maximum compressive stress at midspan is found by superposing
                                               the axial component and the bending component. This gives

                                                                           P   Mc    P    Mc
                                                                      σ c =  +     =   +                          (c)
                                                                           A    I    A    Ak 2
                                               Substituting M max from Eq. (4–48) yields



                                                                        P      ec     l    P
                                                                   σ c =   1 +   sec                           (4–49)
                                                                        A      k 2    2k  EA
                                               By imposing the compressive yield strength S yc as the maximum value of σ c , we can
                                               write Eq. (4–49) in the form

                                                                  P                S yc
                                                                    =                    √                     (4–50)
                                                                               2
                                                                  A    1 + (ec/k ) sec[(l/2k) P/AE]
                                                                                               2
                                               This is called the secant column formula. The term ec/k is called the eccentricity
                                               ratio. Figure 4–21 is a plot of Eq. (4–50) for a steel having a compressive (and tensile)
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