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Thermodynamics    221




























                             Figure 2-34. Thermodynamic properties of carbon dioxide [21]).






                     Referring to Figure 2-35 (process diagram), the first law for this steady-state flow
                     system becomes

                       M(h,-h,)+Q  = (2)(285-315)+60=OBtu/s

                     Because energy is not created, the device does not violate the first law. Application of
                     the second law (Equation 2-1 14) yields


                                                                60
                       P,  = M(S,-S,)+&   = (2)(1.215-1.318)+
                                      Tc                    (-140 + 460)

                          = -0.206+0.1875=  -0.0185Bt~/s*"R
                     Because the rate of entropy production is negative, the device violates the second
                     law and is therefore impossible. Note that the device would be theoretically possible
                     if the final pressure were specified as 400 psia or less by  the inventor. That is, at
                     P,  = 400 psia, T,  = 40°F,  h,  = 290 Btu/lb,,  and S,  = 1.25 Btu/lbm"R, the entropy
                     production rate would be

                       Ps = 2(1.25-1.318)+0.1875  = +0.0515Btu/s*OR

                     Because entropy is produced in this case, the device is theoretically possible.
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