Page 158 - The Combined Finite-Discrete Element Method
P. 158
HOMOGENEOUS DEFORMATION 141
where transformation matrix is given by
∂u ∂u ∂u
1 +
∂x ∂y ∂z
˜ ˜ ˜
i x j x k x
∂v ∂v ∂v
˜ ˜ ˜
i y j y k y = 1 + (4.44)
∂x ∂y ∂z
˜ ˜ ˜
i z j z k z ∂w ∂w ∂w
1 +
∂x ∂y ∂z
By analogy, the components of vector a in the local deformed frame are calculated from
the vector components in the local frame using the following transformation:
j
i ˜x ˜ x k ˜x
a ˜x a x
a ˜y = i ˜y a y
˜ y k ˜y
j (4.45)
a ˜z a z
i ˜z j k ˜z
˜ z
where the transformation matrix is given by
∂u ∂u ∂u
−1
1 +
−1
˜ ˜ ˜ ∂x ∂y ∂z
i ˜x j ˜ x k ˜x i x j x k x
∂v ∂v ∂v
j ˜ ˜ ˜ (4.46)
i ˜y ˜ y k ˜y = i y j y = 1 +
k y
∂x ∂y ∂z
˜
˜
i ˜z j ˜ z k ˜z ˜ i z j z k z ∂w ∂w ∂w
1 +
∂x ∂y ∂z
4.3 HOMOGENEOUS DEFORMATION
Homogeneous deformation can be expressed as a composition of rotation g and stretch s:
f(p) = g◦s 1 = s 2 g (4.47)
◦
The deformation gradient for homogeneous deformation is therefore given by
F = RU = VR (4.48)
where
R =∇g
(4.49)
U =∇s 1
V =∇s 2
It is worth mentioning that by definition of homogeneous deformation tensors F, R and U
are constant tensors, i.e. they do not change from point to point (over the spatial domain).