Page 200 - The Combined Finite-Discrete Element Method
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THE CENTRAL DIFFERENCE TIME INTEGRATION SCHEME        183

           which can be written in matrix form:
                                                 2
                                vh         1   −h k/m     vh
                                       =                                        (5.19)
                                                  2
                                 x         11 − h k/m      x
                                    next                      current
           Thus the central difference scheme for damping a free linear system can be reduced to a
           recursive formula. For the scheme to be stable, it is necessary that the spectral radius of
           the recursive linear operator

                                                   2
                                            1   −h k/m
                                       A =          2                           (5.20)
                                            1  1 − h k/m
           is not greater than one. The associated eigenvalue problem yields the following equation:

                                                 2
                                     1 − λ    −h k/m

                                                2           = 0                 (5.21)
                                       1   1 − h k/m − λ
           which results in the following characteristic equation:

                                            2
                                                        2
                                (1 − λ)(1 − h k/m − λ) + h k/m = 0              (5.22)
           or
                                      2
                                            2
                                     λ + λ(h k/m − 2) + 1 = 0                   (5.23)
           Solution of this equation is given by
                                       2          #   2        2
                                    −(h k/m − 2) ±  (h k/m − 2) − 4
                             λ 1,2 =                                            (5.24)
                                                   2
           which for
                                             2
                                            h k/m = 4                           (5.25)

           results in
                                            λ 1,2 =−1                           (5.26)

           and the spectral radius is equal to 1. For

                                             2
                                            h k/m < 4                           (5.27)
           equation (5.24) yields

                                                   #
                                       2
                                   −(h k/m − 2) ± i 4 − (h k/m − 2) 2
                                                          2
                             λ 1,2 =                                            (5.28)
                                                   2
           and the spectral radius is given by
                                   1    2        2        2        2
                                    #
                         max λ 1,2 =  2  (h k/m − 2) + [4 − (h k/m − 2) ] = 1   (5.29)
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