Page 315 - Thomson, William Tyrrell-Theory of Vibration with Applications-Taylor _ Francis (2010)
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302                      Introduction to the Finite Element Method   Chap. 10

                                                    I  u  I
                                                k   n
                                              -v w w ----- ^  ^F^ku

                                               EA/i   n
                                                          ■F={FA/l)u
                                                                     Figure  10.1-1.
                        10.1  ELEMENT STIFFNESS AND MASS

                                   Axial element.  An element with pinned ends can support only axial forces
                              and  hence  will  act  like  a  spring.  Figure  10.1-1  shows  a  spring  and  a  uniform  rod
                              pinned  to  a  stationary  wall  and  subjected  to  a  force  F.  The  force-displacement
                              relationships for the  two cases  are simply
                                                    Spring        f  = ku
                                                                                         ( 10.1-1)
                                                    Uniform rod

                                   In  general,  these  axial  elements  can  be  a  part  of  a  pin-connected  structure
                              that allows displacement of both ends.  In the finite element method,  the displace­
                              ment and force at each end of the element must be accounted for with proper sign.
                              Figure  10.1-2 shows an axial element labeled with displacements  Wj, U2, and forces
                              Fj, F2,  all  in  the positive  sense.  If we write  the  force-displacement  relationship  in
                              terms of the stiffness matrix,  the  equation  is


                                                                                         ( 10.1-2)
                                                                  ^22
                              The elements of the first column of the stiffness matrix represent the forces at the
                              two  ends  when   =  \  and  U2  =  0,  as  shown  in  Fig.  10.1-3.  Thus,   =  ku^  and
                              F2  =  —kuy
                                   Similarly,  by  letting  U2 =  I  and   =  0,  we  obtain,  as  in  Fig.  10.1-4,  F^  =
                               -ku2  and  F2  =  ku2. Thus,  Eq.  (10.1-2) becomes

                                                                                         (10.1-2')



                                           1       k        2
                                      r                          -^2
                                          F                F          Figure  10.1-2.


                                       pr           k
                                            —-           -.... i
                                           i/,=t
                                                             "2'     Figure  10.1-3.
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