Page 76 - Thomson, William Tyrrell-Theory of Vibration with Applications-Taylor _ Francis (2010)
P. 76

Sec. 3.4   Whirling of Rotating Shafts                          63


                              directions then become
                                            —kr  —cr = ml r —rd^  eo)^ cos (o)i  -   0)]



                                               -   crd  = m\rO   2r0  -  eco^ sin (cot  -   0)j
                              which can be  rearranged to
                                             r -h   +     ~     = eo)^ cos (cot  -   0)   (3.4-3)

                                                 r 0 - f ( ^ r - h 2 r ) ^   = eco^ sin {c ot  -   6 )    (3.4-4)
                                  The  general  case  of  whirl  as  described  by  the  foregoing  equations  comes
                              under  the  classification  of self-excited  motion,  where  the  exciting forces  inducing
                              the  motion  are  controlled  by  the  motion  itself.  Because  the  variables  in  these
                              equations are  r  and  6, the problem is that of 2 DOF.  However, in the steady-state
                              synchronous whirl, where 6  ^  co and  6  =  r =  r  =  0, the problem reduces to that of
                              1  DOF.

                                  Synchronous  whirl.  For  the  synchronous  whirl,  the  whirling  speed  6  is
                              equal  to  the  rotation  speed  o>,  which  we  have  assumed  to  be  constant.  Thus,  we
                              have

                                                            6  —0)
                              and on integrating we obtain
                                                          6  =   cot  —  (f)
                              where  cf)  is the phase angle between  e and  r, which is now a constant, as shown in
                              Fig. 3.4-1.  With  0  =  r  = r =  0,  Eqs.  (3.4-3) and (3.4-4) reduce  to
                                                      k
                                                             r = eco  cos cf)
                                                                                          (3.4-5)
                                                          — cor = eco^ sin 6
                                                          m            ^
                              Dividing, we obtain the following equation  for the phase  angle:
                                                           c
                                                                       0)^
                                                          m          u —
                                                 tan                                      (3.4-6)
                                                         m         1 -

                              where  oo^  =  yjk/m  is  the  critical  speed,  and  ^ =  c/c^.  Noting  from  the  vector
                              triangle of Fig. 3.4-2 that
                                                               k     7
                                                               m
                                                cos (f)
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