Page 331 - Thermodynamics of Biochemical Reactions

Systems of Biochemical Reactions 331

1 2 3 4 5
glc -1 0 0 0 0
atP -1 0 -10 0
96P 1 -10 0 0
adP 1 0 1 0 0
f 6P 0 1 - 1 0 0
f 16bip 0 0 1 - 1 0
dihydroxyacetonephos 0 0 0 1 1
glyceraldehydephos 0 0 0 1 - 1

The vector of standard transformed Gibbs energies of formation at pH 7 and is=0.25 M is

vectorO={glucose,atg,glucose6~hos,adgrfrroxyacetonephos
,glyceraldehyBephos)/.gH->7/.is->.25
{-426.708, -2292.5, -1318.92, -1424.7, -1315.74, -2206.78, -1095.7, -1088.04)

The pathway vector is

vectors={l,l,l,l,l);

vectorG.nu.vectors
-29.105

apparentK=Exp[29.105/(8.31451*.29815)1
125581.

The net reaction is
glc + 2ATP = 2dihydroxyacetonephos + 2ADP

calckprime[glucose+2*atg+de==2*dihydroxyacetonephos+2*adg,7,.251

125587.

6.6 A liter of aqueous solution contains 0.01 mol H2 PO4 - , 0.01 mol HP0, ’-, and 0.01 mol Mg2+. Assuming that the ionic
strength is zero, what is the equilibrium composition of the solution in terms of species at 298.15 K?

(BasicBiochemData has to be loaded)

This problem canbe solved in two different ways. Using equcalcc, the conservation matrix with H, Mg, and P as components
and H+ , Mg2+, Hz PO4 - , HPO, ‘-, and MgHPO, as species is given by

H Mg H2P04- HP042- MgHP04
H 1 0 2 1 1
M g O 1 0 0 1
P 0 0 1 1 1