Page 133 - Bird R.B. Transport phenomena
P. 133

118   Chapter 4  Velocity  Distributions with More Than One Independent Variable
                           It is convenient to introduce the following  dimensionless  variables:


                                                       ^o'        b'       b 2
                           The choices for  dimensionless  velocity  and position ensure that these variables  will go from  0
                           to  1. The choice  of  the dimensionless  time is made so that there will be no parameters occur-
                           ring  in the transformed  partial differential  equation:

                                                             ^  = Л                            (4.1-21)
                                                            д     д
                                                                дт)
                                                             дт
                           The initial  condition is  ф  = 0 at  r  =  0, and  the boundary  conditions are ф  = 1 at  17 = 0 and
                           ф = 0atT7 = 1.
                               We  know  that at infinite  time the system  attains a steady-state  velocity  profile  #00(17) so
                           that at r  =  00 Eq. 4.1-21 becomes
                                                             0  =  — %                          (4.1-22)

                           with  фес = 1 at  77 = 0, and ф  = 0 at  77 = 1. We  then get
                                                 х
                                                            Ф» = 1 -  v                         (4.1-23)
                           for the steady-state limiting  profile.
                               We  then can write
                                                                          )                    (4Л-24)
                           where  ф  is the transient part  of  the solution, which  fades  out as time goes  to infinity.  Substi-
                                  (
                           tution  of  this expression  into the original  differential  equation and boundary conditions then
                           gives for ф {
                                                            %   = Щ                             (4.1-25)

                           with ф[ = ф  at т = 0, and ф  = 0 at  17 = 0 and  1.
                                                  {
                                    ж
                               То solve Eq. 4.1-25 we use the "method of separation  of  (dependent) variables,"  in which
                           we assume a solution  of the form
                                                                                               (4.1-26)
                           Substitution  of this trial solution into Eq. 4.1-25 and then division  by  the product fg  gives
                                                           1
                                                             dg
                                                                   d f
                                                                    2
                                                                 1
                                                               =
                                                                                                 "
                                                           U m                                 (4Л 27)
                           The left  side  is a function  of т alone, and the right side is a function  of  17 alone. This means that
                           both sides must equal a constant. We  choose to designate the constant as  -c 2  (we could  equally
                                        2
                           well use  с or  +c , but  experience  tells us  that these choices make the subsequent  mathematics
                           somewhat more complicated). Equation 4.1-27 can then be separated into two equations
                                                               j-  = ~c g                       (4.1-28)
                                                                     2
                                                                 2
                                                           ^-  + c f=0                          (4.1-29)
                                                           drf
                           These equations has the following  solutions  (see Eqs. C.l-1 and 3):
                                                            g  = Ае~ с2т                        (4.1-30)
                                                       / = В  sin  ст7 + С cos  C77             (4.1-31)
                           in which A,  B, and С are constants of integration.
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