Page 136 - Bird R.B. Transport phenomena
P. 136

§4.2  Solving Flow Problems Using a Stream Function  121

                            Here v° is chosen  to be a complex  function  of y, so that v (y, t) will  differ  from  v (0, t) both in
                                                                         x
                                                                                            x
                            amplitude and phase. We  substitute  this trial solution into Eq. 4.1-44 and obtain
                                                                    ^Г  е'А                     (4.1-49)
                                                                    dy 2  J
                            Next we  make use  of the fact  that, if Щг^ги}  = 9^{zw}, where z  and z  are two  complex quan-
                                                                     2
                                                                              }
                                                                                    2
                            tities and w is an arbitrary  complex quantity, then z x  = z . Then Eq. 4.1-49 becomes
                                                                        2
                                                             _ (^j o  = о                       (4.1-50)
                                                                  v
                            with the following boundary conditions:
                            B.C1:                        aty  = 0,  v°  = v o                   (4.1-51)
                            B.C. 2:                      aty  = °°,  ° = 0                      (4.1-52)
                                                                   v
                            Equation 4.1-50 is  of the form  of  Eq. C.l-4 and has the solution
                                                       o    ^ y     -Vu^>y                     (4.1-53)
                                                      v   =  c   +  Cie
                            Since V/  = ±(1/V2)(1  +  /), this equation can be rewritten as
                                                    °  = q^vW^u+oy  ^-VWWHOJI                   (4.1-54)
                                                    v            +
                            The second boundary  condition requires  that Q = 0, and the first boundary  condition gives
                            C 2  = v . Therefore  the solution to Eq. 4.1-50 is
                                 0
                                                          o   ^-\Яы\ ,у                         (4.1-55)
                                                          v   =  у  +
                            From this result and Eq. 4.1-48, we  get


                                                         —  71 p-vw/2*/y«j(--/(Vw/2i^-wOl       (Л Л Ц,&\

                            or  finally
                                                 v (y,  t) = vtf'^^v  cos (cot - Va>/2vy)        (4.1-57)
                                                  x
                            In this expression,  the exponential describes  the attenuation  of the oscillatory  motion—that is,
                            the decrease  in the amplitude  of the fluid oscillations  with  increasing  distance from  the plate.
                            In  the argument  of the cosine, the quantity  -\/o)/2vy  is called  the phase shift; that is, it de-
                            scribes  how much the fluid oscillations  at a distance у from the wall are "out-of-step" with the
                            oscillations  of the wall itself.
                               Keep in mind that Eq. 4.1-57 is not the complete solution to the problem as stated  in Eqs.
                            4.1-44 to 47, but  only  the "periodic-steady-state"  solution. The complete solution is given in
                            Problem 4D.1.


         .2  SOLVING FLOW      PROBLEMS USING A STREAM FUNCTION

                            Up to this point the examples and  problems have been chosen so  that there was  only  one
                            nonvanishing component of the fluid velocity. Solutions of the  complete Navier-Stokes
                            equation  for flow  in  two  or  three dimensions are  more difficult  to obtain. The basic  pro-
                            cedure  is, of course, similar: one  solves simultaneously  the  equations of continuity  and
                            motion, along with  the  appropriate initial  and  boundary  conditions, to  obtain  the  pres-
                            sure and  velocity profiles.
                               However, having both velocity and  pressure as  dependent variables  in  the  equation
                            of  motion presents  more difficulty  in  multidimensional flow problems  than  in  the  sim-
                            pler  ones  discussed  previously.  It is therefore  frequently  convenient to eliminate  the
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