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304   Chapter 10  Shell Energy  Balances and Temperature Distributions in Solids and Laminar Flow

                                                        Sub-
                                                Substance  Jstance  Substance
                                                  01     12      23

                            t                                     (Ж*

                                 7"
                                                 ТУ/У,
                                  a 1            y///.
                             re,J
                           2    Fluid            4уу                          Fluid
                            2                   *^ (
                            1                    ш
                                                 ш
                           H
                                                                  \^^^      т
                                                                 ^3
                                               Distance,
                           Fig. 10.6-1.  Heat conduction through a composite wall, located be-
                           tween two  fluid  streams at temperatures T  and T .
                                                                  b
                                                             a


                           coefficients  h  and h , respectively.  The anticipated temperature profile  is sketched  in Fig.
                                           3
                                      0
                           10.6-1.
                              First we  set up  the energy  balance  for  the problem.  Since we  are dealing  with  heat
                           conduction in a solid, the terms containing velocity  in the e vector  can be discarded, and
                           the only relevant  contribution is the q vector, describing  heat conduction. We  first  write
                           the energy  balance  for  a slab  of volume  WH Ax

                           Region 01:                 q \ WH  -        = 0                     (10.6-1)
                                                       x x
                           which  states that the heat entering at x must be equal  to the heat leaving at x  +  Ax,  since
                           no heat  is produced  within  the region.  After  division  by  WH  Ax  and  taking  the limit  as
                           Ax  -»  0, we  get

                           Region 01:                                                          (10.6-2)
                                                             dx
                           Integration  of this equation gives
                           Region 01:                 q x  = q 0  (a constant)                 (10.6-3)
                           The constant  of  integration, q ,  is  the heat  flux  at  the plane  x  =  x . 0  The development  in
                                                    0
                           Eqs.  10.6-1, 2, and  3 can be repeated  for  regions  12 and  23 with  continuity conditions on
                           q x  at interfaces,  so that the heat flux is constant and the same  for  all three slabs:
                           Regions  01,12, 23:                 =  <7o                          (10.6-4)

                           with  the same  constant  for  each  of  the regions.  We  may  now  introduce a  Fourier's  law
                           for  each  of the three regions  and  get

                           Region 01:                                                          (10.6-5)
                                                              dx
                                                              [
                                                               dT
                           Region  12:                                                         (10.6-6)
                           Region 23:                          dT                              (10.6-7)
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